Reputation: 145
I tried to get the number of lines of data in several CSV files in VBA. Here is the code.
Sub Woo_Products()
Dim fso As New FileSystemObject
Dim flds As Folders
Dim fls As Files
Dim strText As String
Dim i As Integer
Dim j As Integer
Dim k As Integer
Dim extfind As String
Dim FilePath As String
Dim sLineOfText As String
On Error Resume Next
Workbooks.Open Filename:="F:\Work\scrape\" & "woocommerce-products.csv", UpdateLinks:=3
Set fls = fso.getfolder("C:\Users\star\Downloads").Files
k = 2
For Each f In fls
strText = f.Name
extfind = Right$(strText, Len(strText) - InStrRev(strText, "."))
If extfind = "csv" Then
FilePath = "C:\Users\star\Downloads\" & strText
Open FilePath For Input As #1
i = 0
Do Until EOF(1)
Line Input #1, sLineOfText
If sLineOfText <> "" Then i = i + 1
Loop
Close #1
End If
Next
Windows("woocommerce-products.csv").Activate
ActiveWorkbook.Save
ActiveWorkbook.Close
End Sub
But I am getting the same count for each file. Of course, each file has different lines of data. Hope to help me for this.
Upvotes: 2
Views: 8155
Reputation: 145
i = ActiveWorkbook.ActiveSheet.Cells(ActiveWorkbook.ActiveSheet.Rows.Count, 1).End(xlUp).Row
It's working so well.
Upvotes: -2
Reputation: 929
You'll need to add the references (Tools --> References)
Microsoft Scripting Runtime
Microsoft VBScript Regular Expressions 5.5
This will count "Return & NewLine" characters in the file.
Private Function LineCount(ByVal PathFile As String) As Long
Dim sData As String
Dim oFile As New FileSystemObject
sData = oFile.OpenTextFile(PathFile, ForReading).ReadAll
Dim oRegX As New RegExp
oRegX.Pattern = "\r\n"
oRegX.Global = True
LineCount = oRegX.Execute(sData).Count + 1
Set oRegX = Nothing
Set oFile = Nothing
End Function
Upvotes: 2
Reputation: 8518
Another approach using FileSystemObject
:
Public Function GetLineCount(ByVal Path As String) As Long
With CreateObject("Scripting.FileSystemObject")
GetLineCount = UBound(Split(.OpenTextFile(Path, 1).ReadAll, vbNewLine)) + 1
End With
End Function
Upvotes: 3
Reputation: 7759
If all you need is a line count, I would write a function to return the count.
Function getFileLineCount(FullFileName As String, Optional LineDelimiter As String = vbNewLine) As Long
Dim text As String
Dim fileNo As Integer, n As Long
fileNo = FreeFile
Open FullFileName For Input As #fileNo
Do Until EOF(1)
Line Input #1, text
n = n + 1
Loop
Close #fileNo
getFileLineCount = n
End Function
Upvotes: 4