CODEWITHSUNDEEP
vim
sidyll
sidyll

Reputation: 59277

Beginner scripting: ^@ appearing at the end of text

I'm trying to create a script that helps creating shebangs (Ok, it may not be that useful but has advantages when you don't know where the program is, for example), here's what I have so far:

function! CreateShebang()
    call inputsave()
    let program = input('Enter the program name: ')
    call inputrestore()
    let path = system('which ' . program)
    call append(0, '#!' . path)
endfunction

By the way, I'm just starting with vim scrips, so if you notice any wrong function and concepts or know a better way to achieve the result, please tell me. Any help is really appreciated.

The big problem is that after running, the scripts prompts for the program name correctly and then add something like this to the file:

#!/usr/bin/perl^@

What's that ^@ doing there?

Also, If I may ask another question here, how can I clear the command line after input()? The text entered by the user keeps showing until another command is entered.

Upvotes: 3

Views: 766

Answers (2)

Benoit
Benoit

Reputation: 79155

Probably the which command output contains the NULL character.

The system() function replaces line breaks with <NL>s. (from :help system()). Therefore you could do:

let path = substitute(system('which ' . program), '\%x00', '', 'g')

Otherwise you could do the following:

function! CreateShebang()
    call inputsave()
    0 put = '#!/usr/bin/env ' . input('Enter the program name: ')
    call inputrestore()
endfunction

Upvotes: 1

ZyX
ZyX

Reputation: 53604

^@ at the end of command is a newline translated to NULL by append() function, see :h NL-used-for-Nul (it the reason why your substitute(...\%d000...) worked while you don't have NULL in your string). As which command always outputs newline at the end of string, I suggest you to slightly modify your code by adding [:-2] to the end of the system() call. This construction will strip just the last byte of function output:

let path = system('which ' . program)[:-2]

If you use substitute, use

let path=substitute(path, '\n', '', 'g')

, don't confuse yourself with \%d000 which is semantically wrong.

Upvotes: 4

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