Reputation: 77
I have data in my sql like: 2018-06-26 07:15:06 Right now I am using: $sqlq = "Select * from db WHERE date LIKE '$myDato' "; $myDato is set as: 2018-06-26% This works like a charm. I am getting all rows starting with that day. Now i want to extract more days. I have tried:
$sqlq = "Select * from db WHERE date BETWEEN >= '$myDato' AND => '$myDato2'";
$sqlq = "Select * from db WHERE date BETWEEN LIKE '$myDato' AND LIKE '$myDato2'";
$sqlq = "Select * from db WHERE date BETWEEN '$myDato' AND '$myDato2'";
but i can't find the right one.
Upvotes: 0
Views: 49
Reputation: 4840
Try this:
$sqlq = "Select * from db WHERE date >= '$myDato' AND date >= '$myDato2'";
If there is something like %
in the end of date, then following solution can be used.
$sqlq = "Select * from db WHERE date >= '" . substr($myDato, 0, -1) . "' AND date >= '" . substr($myDato2, 0, -1) . "'";
substr($myDato, 0, -1)
will remove the last character from string.
Upvotes: 2
Reputation: 744
Use this:-
$sqlq = "Select * from db WHERE date >= '".$myDato."' AND date <= '".$myDato2."' ";
Upvotes: 0
Reputation: 29
For example get sql data between '2018-06-26' and '2018-06-27'
SELECT * FROM db WHERE STR_TO_DATE(`date`, '%Y-%m-%d %H:%i:%s') BETWEEN STR_TO_DATE('2018-06-26', '%Y-%m-%d %H:%i:%s') AND STR_TO_DATE('2018-06-27', '%Y-%m-%d %H:%i:%s')
Upvotes: 0
Reputation: 141
Select * from db WHERE date >='2018-06-26 07:15:06' AND date< "2018-06-30 07:15:06";
Upvotes: 0