CODEWITHSUNDEEP
javascriptarrayssortingdate
Shifut Hossain
Shifut Hossain

Reputation: 1699

How can I find closest date value from an array according to the current date?

I want to get the next closest date on this array according to the current date.

var dates = [
    'Aug 18, 2018 03:24:00',
    'August 19, 2018 03:24:00',
    'September 17, 2018 03:24:00',
    'September 14, 2018 03:24:00',
    'August 18, 2018 03:24:00',
    'July 16, 2018 03:24:00',
    'July 15, 2018 03:24:00',
    'December 15, 2018 03:24:00',
    'July 13, 2018 03:24:00',
];

    var now = new Date();

Upvotes: 0

Views: 4498

Answers (4)

Dženis H.
Dženis H.

Reputation: 7822

You can use moment.js library to convert your dates in any format you want. You can achieve that simply by mapping over your array and by using the
moment(yourDate).format(your format) functionality.

Here's a little function that can help you:
It has 2 parameters ->

  • a) dates -> which are your array of dates &&
  • b) target which is the value you're comparing it to.

.

const dates = [
                '1980-7-12',
                '2001-1-5',
                '2018-4-12',
                '1999-3-25'
            ];   

    const nearestDate = (dates, target) => {
          if (!target

) target = Date.now()
      else if (target instanceof Date) target = target.getTime()

      let nearest = Infinity
      let winner = -1

      dates.forEach(function (date, index) {
        if (date instanceof Date) date = date.getTime()
        let distance = Math.abs(date - target)
        if (distance < nearest) {
          nearest = distance
          winner = index
        }
      })

      return winner
    }

Upvotes: 0

Leonid Pyrlia
Leonid Pyrlia

Reputation: 1702

You can sort the dates array by the absolute difference between current date and extract the first item:

var dates = [
    'Aug 18, 2018 03:24:00',
    'August 19, 2018 03:24:00',
    'September 17, 2018 03:24:00',
    'September 14, 2018 03:24:00',
    'August 18, 2018 03:24:00',
    'July 16, 2018 03:24:00',
    'July 15, 2018 03:24:00',
    'December 15, 2018 03:24:00',
    'July 13, 2018 03:24:00',
];

var now = new Date();

var [ closest ] = dates.sort((a,b) => {

  const [aDate, bDate] = [a,b].map(d => Math.abs(new Date(d) - now));

  return aDate - bDate;

});

console.log(closest);

Upvotes: 0

Arman Charan
Arman Charan

Reputation: 5797

See Array.prototype.reduce() for more info.

// Input.
const dates = ['July 16, 1995 03:24:00','Aug 18, 1995 03:24:00','August 19, 1995 03:24:00','September 17, 1995 03:24:00','September 14, 1995 03:24:00','August 18, 1995 03:24:00','July 16, 1995 03:24:00','December 15, 1995 03:24:00','July 13, 1995 03:24:00']

// Closest Date.
const closestDate = dates => dates.reduce((x, date) => {
  const distance = Math.abs(Date.now() - new Date(date))
  if (!x.distance || distance < x.distance) return {distance, date}
  return x
}, {}).date

// Output + Proof.
const output = closestDate(dates)
console.log(output)

Upvotes: 0

Joven28
Joven28

Reputation: 769

First you need to convert each date into a timestamp then subtract each of them by the current date and store the timestamp difference in the temp array then get the index of the minimum value and use the index to access the closest date in the original array.

var dates = [
    'July 16, 1995 03:24:00',
    'Aug 18, 1995 03:24:00',
    'August 19, 1995 03:24:00',
    'September 17, 1995 03:24:00',
    'September 14, 1995 03:24:00',
    'August 18, 1995 03:24:00',
    'July 16, 1995 03:24:00',
    'December 15, 1995 03:24:00',
    'July 13, 1995 03:24:00',
]

var temp = dates.map(d => Math.abs(new Date() - new Date(d).getTime()));
var idx = temp.indexOf(Math.min(...temp));
console.log(dates[idx]);

Upvotes: 2

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