CODEWITHSUNDEEP
pythonexceptiontry-catch
CDNthe2nd
CDNthe2nd

Reputation: 369

Python - Exception gives 'Connection aborted' - how can I skip it and continue

So basically i'm using requests where I sometimes enter a URL and gives me an error saying:

('Connection aborted.', RemoteDisconnected('Remote end closed connection without response',))

which is fine when I do a new requests again or with sleep which I do like this now:

 except Exception as e:
        logger.error(e)
        randomtime = random.randint(1,5)
        logger.warn('ERROR - Retrying again website %s, retrying in %d secs' % (url, randomtime))
        time.sleep(randomtime)
        continue

and what I want to do is that whenever this error comes again as ERROR - I just want to basically 'skip' it meaning that it shouldn't give me a print of it but if there comes another error that is NOT 

('Connection aborted.', RemoteDisconnected('Remote end closed connection without response',))

then it should print the error.

What do I need to do to make it print other errors but just continue with the Connection aborted without printing it?

Upvotes: 2

Views: 5769

Answers (3)

Simas Joneliunas
Simas Joneliunas

Reputation: 3118

You should except RemoteDisconected separately from other exceptions:

from http.client import RemoteDisconnected    
try:
   ...
except RemoteDisconnected:
    continue
except Exception as e:
    logger.error(e)
    randomtime = random.randint(1,5)
    logger.warn('ERROR - Retrying again website %s, retrying in %d secs' % (url, randomtime))
    time.sleep(randomtime)
    continue

Upvotes: 2

phil
phil

Reputation: 518

You can catch the RemoteDisconnected exception with:

try:
    #your code here
except requests.exceptions.ConnectionError as e:
    pass
except Exception as e:
    logger.error(e)
    randomtime = random.randint(1,5)
    logger.warn('ERROR - Retrying again website %s, retrying in %d secs' % (url, randomtime))
    time.sleep(randomtime)
    continue

Although be careful about catching exceptions quietly, it may cause you problems later by stopping you identify the true cause of an issue.

Upvotes: 4

lenik
lenik

Reputation: 23538

You may try this:

if str(e) != 'Connection aborted.' :
    logger.error(e)

However, connection can be aborted because of many different reasons, and you may want to add additional checks into the if statement, checking e.reason or other available fields.

Upvotes: 3

Related Questions