CODEWITHSUNDEEP
c++
Ferit Yiğit BALABAN
Ferit Yiğit BALABAN

Reputation: 105

How to append a char type variable to a string?

I want to append a char-variable containing the password to a string saying "Your password is: ". When I use the append function for this I get an error saying I can't use this function with string. (I can only use it with unsigned int and char.)

char pass[64];
std::cout << "Enter a password: "; fgets(pass, 64, stdin);    
std::string ssifre = "Your password is: "; ssifre.append(sizeof(pass), pass);

If you know another way to solve this, please comment. I don't need to use this function.

Upvotes: 3

Views: 282

Answers (2)

Remy Lebeau
Remy Lebeau

Reputation: 598134

ssifre.append(sizeof(pass), pass) is trying to call the append(size_type count, CharT ch) overloaded version, which appends ch count times. That does not work since pass[] is not a single char, it is an array of chars.

You need to use the append(const CharT* s) overloaded version instead (especially since fgets() ensures that pass[] will be null-terminated, and append(const CharT* s) expects a null-terminated char* string). A fixed char[] array decays into a char* pointer to the 1st char element:

ssifre.append(pass);

That being said, you really shouldn't be using a char[] array in this situation to begin with. You should be reading in a std::string instead:

std::string pass;
std::cout << "Enter a password: ";
std::getline(std::cin, pass);
std::string ssifre = "Your password is: " + pass;

Upvotes: 0

Olivier Sohn
Olivier Sohn

Reputation: 1322

This should work:

ssifre += pass;

It's using the += operator

(note that as @MichaelDoubez mentionned in the comments, ssifre.append(pass) would work, too.)

Upvotes: 4

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