Reputation: 449
I am trying to calculate the difference between given two times and i find some problem in it. Suppose we have times value are "11:AM" and 10:00 AM". I am able to calculate but there is a bit of confusion in AM ,PM. Thanks in advance
I am using following code:
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
public class StringToDate {
public static String timeDiff(String time1, String time2) {
String Time = null;
int difference;
String a1 = time1.substring(6);
String a2 = time2.substring(6);
try {
// Define a date format the same as the expected input
SimpleDateFormat sdf = new SimpleDateFormat("HH:mm a");
// Get time values of the date objects
long l1 = sdf.parse(time1).getTime();
long l2 = sdf.parse(time2).getTime();
difference = (int) (l2 - l1);
difference = (difference < 0 ? -difference : difference) / 60000;
if (difference > 60) {
int Hour = difference / 60;
int Mins = difference % 60;
if (Mins == 0)
Time = Hour + " Hours";
else
Time = Hour + " Hours" + " " + Mins + " Mins";
} else {
Time = difference + " " + "Mins";
}
} catch (ParseException e) {
e.printStackTrace();
}
return Time;
}
public static void main(String[] args) {
String diff = StringToDate.timeDiff("10:00 AM", "01:00 PM");
System.out.println("Difference: " + diff);
}
}
Upvotes: 1
Views: 4471
Reputation: 5448
For String / Date conversion and / or calculation I recommend you the utilities of Apache Commons: https://commons.apache.org/lang/api-2.6/index.html
Always useful and no need to reinvent the wheel...
Update: I recently used another library: JodaTime which was very useful for all the date manipulation.
Upvotes: 0
Reputation: 21
To calculate the difference between two times in 12 hour AM/PM format, try this:
try {
SimpleDateFormat format = new SimpleDateFormat("hh:mm:ss a");
Date d1 = format.parse("11:59:30 PM");
Date d2 = format.parse("12:01:00 AM");
System.out.println("=== Start* :: "+ timeStart);
System.out.println("=== End* :: "+ timerEndOrCurrent);
long difference = d2.getTime() - d1.getTime();
int days = (int) (difference / (1000*60*60*24));
int hours = (int) ((difference - (1000*60*60*24*days)) / (1000*60*60));
long min = (int) (difference - (1000*60*60*24*days) - (1000*60*60*hours)) / (1000*60);
hours = (hours < 0 ? -hours : hours);
long sec = (int) (difference / 1000) % (60);
System.out.println("=== hours :: "+ hours);
System.out.println("=== min :: "+ ( min < 0 ? ((min-1)+60) : min));
System.out.println("=== sec :: "+ ( sec < 0 ? -sec : sec));
System.out.println("");
} catch (ParseException e1) {
e1.printStackTrace();
}
Upvotes: 0
Reputation: 11
only the format was incorrect... the line
SimpleDateFormat sdf=new SimpleDateFormat("HH:mm a");
should be changed to
SimpleDateFormat sdf=new SimpleDateFormat("hh:mm a");
everything should be fine after that.
Upvotes: 1
Reputation: 6054
Since you already have a way to calculate the difference if they are the same AM/PM, you just have to convert them to 24-hour scale:
if(time.isPM())
//add 12 hours to time
and then do your calculations (assuming they are in the same day). This is also assuming you are not just using the Java Calendar class:
http://download.oracle.com/javase/1.5.0/docs/api/java/util/Calendar.html
With Calendar, you can just call
Calendar.getTimeInMillis()
and subtract them from each other.
Upvotes: 1
Reputation: 101
You can get date objects for both start & end time. Then get time in millis & subtract.
Difference in Millis = endDate.getTime() - startDate.getTime()
Convert the difference to hours/minutes.
Upvotes: 6