Reputation: 71
Hi I currently have a function that is able to split values in a same cell that is delimited by a new line. However the function below only accepts me to pass through one column at a time was thinking if there is any other ways that I can pass it through multiple columns or in fact the whole dataframe.
A sample would be like this
A B C
1\n2\n3 2\n\5 A
The code is below
def tidy_split(df, column, sep='|', keep=False):
indexes = list()
new_values = list()
df = df.dropna(subset=[column])
for i, presplit in enumerate(df[column].astype(str)):
values = presplit.split(sep)
if keep and len(values) > 1:
indexes.append(i)
new_values.append(presplit)
for value in values:
indexes.append(i)
new_values.append(value)
new_df = df.iloc[indexes, :].copy()
new_df[column] = new_values
return new_df
It currently works when I run
df1 = tidy_split(df, 'A', '\n')
After running the function of selecting only column A
A B C
1 2\n5 A
2 2\n5 A
3 2\n5 A
I was hoping to be able to pass in more than just an accepted argument and in this case splitting column 'B' as well. Previously I have attempted passing in lambda or attempted using apply but it requires a positional argument which is 'column'. Would appreciate any help given! Was thinking if a loop is possible
EDIT: Desired output as each number refer to something important Before
A B C
1\n2\n3 2\n5 A
After
A B C
1 2 A
2 5 A
3 n/a A
Upvotes: 0
Views: 125
Reputation: 2152
Input:
A B C
0 1\n2\n3 2\n5 A
Code:
import pandas as pd
cols = df.columns.tolist()
# create list in each cell by detecting '\n'
for col in cols:
df[col] = df[col].apply(lambda x: str(x).split("\n"))
# empty dataframe to store result
dfs = pd.DataFrame()
# loop over rows to construct small dataframes
# and then accumulate each to the resulting dataframe
for ind, row in df.iterrows():
a_vals = row['A']
b_vals = row['B'] + ["n/a"] * (len(a_vals) - len(row['B']))
c_vals = row['C'] + [row['C'][0]] * (len(a_vals) - len(row['C']))
temp = pd.DataFrame({'A': a_vals, 'B': b_vals, 'C': c_vals})
dfs = pd.concat([dfs, temp], axis=0, ignore_index=True)
Output:
A B C
0 1 2 A
1 2 5 A
2 3 n/a A
Upvotes: 1