CODEWITHSUNDEEP
phpfor-loop
Peter
Peter

Reputation: 2306

Creating arrays in for loops

I'm starting with a csv variable of column names. This is then exploded into an array, then counted and tossed into a for loop that is supposed to create another array.

Every time I run it, it goes into this endless loop that just hammers away at my browser...until it dies. :(

Here is the code..

$columns = 'id, name, phone, blood_type';

$column_array = explode(',',$columns);  
$column_length = count($column_array);  

//loop through the column length, create post vars and set default  
for($i = 0; $i <= $column_length; $i++)  
{  
    $array[] = $iSortCol_.$i = $column_array[$i];
    //create the array iSortCol_1 => $column_array[1]...  
    //$array[] = 'iSortCol_'.$i = $column_array[0];  
}

What I would like to get out of all this is a new array that looks like so..

$goal = array(  
    "iSortCol_1" => "id",    
    "iSortCol_2" => "name",  
    "iSortCol_3" => "phone",  
    "iSortCol_4" => "blood_type"  
);

Upvotes: 1

Views: 172

Answers (3)

Russell Dias
Russell Dias

Reputation: 73292

Simply change 

$array[] = 'iSortCol_'.$i = $column_array[0];

to 

$array['iSortCol_'.$i] = $column_array[$i];

and the <= to < in your for loop, otherwise you will display a blank array value in your end result. Because you need to go up to but not including the length of $column_array.

Upvotes: 2

JohnP
JohnP

Reputation: 50019

$array[] = 'iSortCol_'.$i = $column_array[0];

I think it's because you're assigning the value of $column_array[0] to $i AND using it as the loop index. Use another variable to do that, otherwise it just goes on and on.

EDIT Tested and pasted output

Working code, just tested it on local

$columns = 'id, name, phone, blood_type';
$column_array = explode(',',$columns);  
$column_length = count($column_array);  
$array   = array();
for($i = 0; $i < $column_length; $i++)  
{  
    //create the array iSortCol_1 => $column_array[1]...  
    $array['iSortCol_'.$i] = $column_array[$i];  
}  

var_dump($array);

This will output 

array
  'iSortCol_0' => string 'id' (length=2)
  'iSortCol_1' => string ' name' (length=5)
  'iSortCol_2' => string ' phone' (length=6)
  'iSortCol_3' => string ' blood_type' (length=11)

Is this not what you want?

Upvotes: 1

GolezTrol
GolezTrol

Reputation: 116110

I think you meant to write:

$array['iSortCol_'.$i] = $column_array[0];

Upvotes: 0

Related Questions