Reputation: 6415
I've got a page that has a dropdown menu, and upon selection, creates a new element (a table) using an AJAX call. Firebug shows this on action:
The actual code for this is:
select name="category" id="category" onchange="load(this.value)
However, in addition to it creating a new table, I'd like it to destroy/ not display another table that's already on the page. The table has class="table2" id="PR". What additional code do I put into that select tag above? Thanks
Upvotes: 1
Views: 2012
Reputation: 4699
Without jQuery try:
onchange="load(this.value); document.getElementById('table1').style.display='none';"
Upvotes: 0
Reputation: 35793
I would change it so you have this code instead:
$(function() {
$('#category').change(function() {
load($(this).val());
$('#PR').hide(); // or .remove() if you want to completely remove it;
});
});
You can then remove the onchange from the select tag as it is wired up via the jquery event.
Upvotes: 2
Reputation: 2712
Try with the following:
$('#PR').remove();
But maybe you'll need to make a function to call onchange:
function mychange(event)
{
load( event.currentTarget.value );
$('#PR').remove();
}
select name="category" id="category" onchange="mychange(event)"
Upvotes: 3