Reputation: 392
I have 2 columns like this:
0.0 1.2
0.0 2.3
0.0 1.5
0.1 1.0
0.1 1.2
0.1 1.4
0.1 1.7
0.4 1.1
0.4 1.3
0.4 1.5
In the 1st column, 0.0 is repeated 3 times. I want to sum corresponding elements (1.2 + 2.3 + 1.5) in the 2nd column. Similarly, 0.1 is repeated 4 times in the 1st column. I want to sum the corresponding elements (1.0 + 1.2 + 1.4 + 1.7) in the 2nd column and so on.
I am trying like this
for i = 1:length(col1)
for j = 1:length(col2)
% if col2(j) == col1(i)
% to do
end
end
end
Upvotes: 2
Views: 107
Reputation: 112659
This is a classical use of unique
and accumarray
:
x = [0.0 1.2
0.0 2.3
0.0 1.5
0.1 1.0
0.1 1.2
0.1 1.4
0.1 1.7
0.4 1.1
0.4 1.3
0.4 1.5]; % data
[~, ~, w] = unique(x(:,1)); % labels of unique elements
result = accumarray(w, x(:,2)); % sum using the above as grouping variable
You can also use the newer splitapply
function instead of accumarray
:
[~, ~, w] = unique(x(:,1)); % labels of unique elements
result = splitapply(@sum, x(:,2), w); % sum using the above as grouping variable
Upvotes: 6
Reputation: 35525
a=[0.0 1.2
0.0 2.3
0.0 1.5
0.1 1.0
0.1 1.2
0.1 1.4
0.1 1.7
0.4 1.1
0.4 1.3
0.4 1.5]
% Get unique col1 values, and indices
[uniq,~,ib]=unique(a(:,1));
% for each unique value in col1
for ii=1:length(uniq)
% sum all col2 values that correspond to the current index of the unique value
s(ii)=sum(a(ib==ii,2));
end
Gives:
s =
5.0000 5.3000 3.9000
Upvotes: 2