Reputation: 69
I'm reviewing mysql and I am working on composing foreign keys when creating tables. However when I create the foreign key I receive a syntax error.
CREATE TABLE IF NOT EXISTS staff (
staff_id INT(5) NOT NULL,
staff_first_name VARCHAR(20) NOT NULL,
staff_last_name VARCHAR(20) NOT NULL,
staff_phone_number VARCHAR(15) NOT NULL,
staff_email_address VARCHAR(30) NOT NULL,
CONSTRAINT staff_id_pk PRIMARY KEY (staff_id)
CONSTRAINT staff_id_fk FOREIGN KEY (staff_id)
REFERENCES computer_staff (staff_id)
);
Can anyone see what I've done wrong here?
EDIT:
The error I receive reports as:
19:35:55 CONSTRAINT staff_id_fk FOREIGN KEY (staff_id), REFERENCES computer_staff (staff_id)) Error Code: 1064. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CONSTRAINT staff_id_fk FOREIGN KEY (staff_id), REFERENCES computer_staff (staff_' at line 1 0.00025 sec
UPDATE: Error Code: 1215. Cannot add foreign key constraint 0.110 sec
How does one resolve error code 1215??
Upvotes: 1
Views: 782
Reputation: 186
Try this code
CREATE TABLE IF NOT EXISTS staff (
staff_id INT(5) NOT NULL,
staff_first_name VARCHAR(20) NOT NULL,
staff_last_name VARCHAR(20) NOT NULL,
staff_phone_number VARCHAR(15) NOT NULL,
staff_email_address VARCHAR(30) NOT NULL,
Foregn_Key int,
CONSTRAINT staff_id_pk PRIMARY KEY (staff_id),
CONSTRAINT staff_id_fk FOREIGN KEY (Foregn_Key)
REFERENCES computer_staff (Foregn_Key)
);
Upvotes: 2
Reputation: 176189
You are missing comma:
CREATE TABLE IF NOT EXISTS staff (
staff_id INT(5) NOT NULL,
staff_first_name VARCHAR(20) NOT NULL,
staff_last_name VARCHAR(20) NOT NULL,
staff_phone_number VARCHAR(15) NOT NULL,
staff_email_address VARCHAR(30) NOT NULL,
CONSTRAINT staff_id_pk PRIMARY KEY (staff_id), -- here
CONSTRAINT staff_id_fk FOREIGN KEY (staff_id)
REFERENCES computer_staff (staff_id)
);
Upvotes: 2