CODEWITHSUNDEEP
pythonpython-3.x
outcast_dreamer
outcast_dreamer

Reputation: 163

exception handling mistake

So I have a condition for accepting only a negative value for a variable and it should also not raise a value error. My code goes like this ->

try:
    x = int(input("Enter -ve value : "))
    while x >= 0:
        print("Error wrong value!")
        x = int(input("Enter -ve value : " )
except ValueError:
    print("Error wrong value!")
    x = int(input("Enter -ve value : "))
    while x >= 0:
        print("Error wrong value!")
        x=int(input("Enter -ve value : " )

The only problem with this approach is that, suppose I press enter without entering a value for the first time. It takes me to the "except" condition and it works fine but if I enter a blank value again my code stops because of value error. How do I stop this from happening? Is there a more efficient way of writing this code without importing any modules?

Thank you for your time and efforts! I wrote this question on the mobile app so sorry if it causes any inconvenience!

Upvotes: 0

Views: 41

Answers (1)

AJC24
AJC24

Reputation: 3336

You could try it like this:

x = 0
while x >= 0:
    try:
        x = int(input("Enter -ve value : "))
    except ValueError:
        print("Error wrong value!")
        x = 0

This will achieve what you are asking for in that it will keep prompting you to enter a number while x >= 0 and will also ensure the exception handling is always carried out on each input too.

Upvotes: 4

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