CODEWITHSUNDEEP
javascriptnode.jsexpressasynchronous
pr0p
pr0p

Reputation: 2358

Calling a async function

I have a module as follows:

async.js

module.exports = async function (){
    await func()
}

index.js

var asyncFun = require('async')

How do i run it directly as asyncFun() in index.js ?

I know how to run these functions as middlewares but i want to run it directly. As for running it i need to call await and await cannot be called without being inside async.

Upvotes: 3

Views: 2979

Answers (3)

Guerric P
Guerric P

Reputation: 31833

As you are using CommonJS, you cannot use await at top-level (contrary to ECMAScript modules) but you can get around it with this:

(async () => {
    await asyncFun();
    // Do something else
})();

In an ECMAScript module, since ECMAScript 2022 (ES13) it is possible to use a top-level await:

await asyncFun();
// Do something else

If you don't need to chain other instructions after the Promise returned by asyncFun has resolved, then you don't need await at all:

asyncFun();

Upvotes: 7

pr0p
pr0p

Reputation: 2358

I solved this question by making the root function async and wrapping all the async function with a normal function and the async function returning a promise. ( using a calling).

Example :

Assume this is the main function where you write all the code.

// create it as a async function
module.exports = async function main(){
    // Do something all your stuff
}

Call your main function from else where

require('./main)()

Upvotes: 0

Tushar Nikam
Tushar Nikam

Reputation: 624

try adding return statement in async.js

module.exports = async function (){
    return await func()
}

and run asyncFun() directly

Upvotes: 0

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