Reputation: 1422
I have this function that gives me all the numbers from 1
to 870
. How can I get the 870
(the last item) and add a Class to it?
Thanks in advance.
var points = new Array(870);
for (var i = 0; i < 870; i++){points[i] = i + 1;}
$(".numbers").html(points.join(', '))
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class=numbers></div>
Upvotes: 1
Views: 861
Reputation: 36331
What you could do is use the :last-child
selector on the numbers
class, and add it that way like so:
var points = new Array(870);
for (var i = 0; i < 870; i++) {
points[i] = `<span>${i + 1}</span>`
}
$(".numbers").html(points.join(' '))
.find(':last-child')
.addClass('myClass')
.myClass {
color: red;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="numbers"></div>
Upvotes: 2
Reputation: 7933
Add a span
element and a custom class to it to the last point.
For dynamic array use point.length-1
instead 869
var points = new Array(870);
for (var i = 0; i < 870; i++){points[i] = i + 1;}
points[points.length-1] = '<span class="custom-class">'+points[points.length-1]+'</span>'
$(".numbers").html(points.join(', '))
.custom-class{
color: red;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class=numbers></div>
Upvotes: 3