Reputation: 865
My original query was to select data from phpadmin table and display into table.
$sql="select * from table";
$result=mysql_query($sql) or die(mysql_error());
while($myrow=MySQL_fetch_array($result,MYSQL_ASSOC))
{
extract($myrow);
echo "<td align='left' bgcolor='$bgclr'>".$myrow[0]."</td>";
echo "<td align='left' bgcolor='$bgclr'>".$myrow[1]."</td>";
echo "<td align='left' bgcolor='$bgclr'>".$myrow[2]."</td>";
echo "<td align='left' bgcolor='$bgclr'>".$myrow[3]."</td>";
}
Then I need to display another column using value of $myrow[0]
to execute another query to get the value.
$sql="select * from table";
$result=mysql_query($sql) or die(mysql_error());
while($myrow=MySQL_fetch_array($result,MYSQL_ASSOC))
{
extract($myrow);
$id = $myrow[0];
$sql="select amount from table2 where id like '%$id%'";
$result = mysqli_query($conn, $sql);
echo "<td align='left' bgcolor='$bgclr'>".$myrow[0]."</td>";
echo "<td align='left' bgcolor='$bgclr'>".$myrow[1]."</td>";
echo "<td align='left' bgcolor='$bgclr'>".$myrow[2]."</td>";
echo "<td align='left' bgcolor='$bgclr'>".$myrow[3]."</td>";
while ($row=mysqli_fetch_row($result)) {
echo "<td align='left' bgcolor='$bgclr'>".$row[0]."</td>";echo "</tr>";
}
}
And my page became blank. And the error was at
$result = mysqli_query($conn, $sql);
Is it the correct method or how should I do it?
Upvotes: 0
Views: 5440
Reputation: 4860
You overwrite variable $result
while executing query inside the loop here:
$sql="select amount from table2 where id like '%$id%'";
$result = mysqli_query($conn, $sql);
Change variable name $result
inside the loop and code will be like:
$sql="select amount from table2 where id like '%$id%'";
$result2 = mysqli_query($conn, $sql);
Also update it here:
while ($row=mysqli_fetch_row($result2)) {
echo "<td align='left' bgcolor='$bgclr'>".$row[0]."</td>";echo "</tr>";
}
}
Upvotes: 3