CODEWITHSUNDEEP
swiftxmppframework
Fattaneh Talebi
Fattaneh Talebi

Reputation: 767

How to extract receive message body from XMPPMessage?

I get all messages sent to me from all users.
When I get the result it is type of XMPPMessage, I don't know how to extract body from this

This problem is related to get archived messages.

func getALLMessagesFromServerWithXML() {
    let query = try? XMLElement(xmlString: "<query xmlns='urn:xmpp:mam:2'/>")
    let iq = XMLElement.element(withName: "iq") as? XMLElement
    iq?.addAttribute(withName: "type", stringValue: "set")
    iq?.addAttribute(withName: "id", stringValue: "getAllMesseges")
    if let aQuery = query {
        iq?.addChild(aQuery)
    }

    xmppStream.send(iq!)
}

The result is gotten from this method:

func xmppStream(_ sender: XMPPStream, didReceive message: XMPPMessage) {
    print(message)
}

Output

<message xmlns="jabber:client" to="f.talebi@x/1516292205485357040111042" from="f.talebi@x"><result xmlns="urn:xmpp:mam:2" id="1530957470465122"><forwarded xmlns="urn:xmpp:forward:0"><message xmlns="jabber:client" lang="en" to="[email protected]" from="[email protected]/134788006381643425047394" type="chat"><archived xmlns="urn:xmpp:mam:tmp" by="[email protected]" id="1530957470465122"></archived><stanza-id xmlns="urn:xmpp:sid:0" by="[email protected]" id="1530957470465122"></stanza-id><body>hi 2018-07-07 09:57:49 +0000</body></message><delay xmlns="urn:xmpp:delay" from="x.ir" stamp="2018-07-07T09:57:50.465122Z"></delay></forwarded></result></message>

How can I extract body from this output? for normal messages I can get body by message.body but for the archived messages I cannot get body with this code.

According to @andesta.erfan answer, I added these codes:

variable:

private var archiving = XMPPMessageArchiveManagement()

in init()

archiving = XMPPMessageArchiveManagement(dispatchQueue: DispatchQueue.main)
archiving?.activate(xmppStream)    
archiving?.addDelegate(self, delegateQueue: DispatchQueue.main)

Extension implementation:

extension XMPPHelper: XMPPMessageArchiveManagementDelegate {

    func xmppMessageArchiveManagement(_ xmppMessageArchiveManagement: XMPPMessageArchiveManagement, didReceiveMAMMessage message: XMPPMessage) {
        print(message.body())
    }

}

But xmppMessageArchiveManagement is never called, xmppStream(_ sender: XMPPStream, didReceive message: XMPPMessage) is called in both situation. when it is an archived message or the normal one.

Upvotes: 0

Views: 1643

Answers (3)

Harshal Valanda
Harshal Valanda

Reputation: 5451

Swift 4.2

XMPPStreamDelegate

func xmppStream(_ sender: XMPPStream, didReceive message: XMPPMessage) {
     let body = message.body
}

XMPPMessageArchiveManagementDelegate

func xmppMessageArchiveManagement(_ xmppMessageArchiveManagement: XMPPMessageArchiveManagement, didReceiveMAMMessage message: XMPPMessage) {
  if let xmppMessage = message.mamResult?.forwardedMessage {
     let body = xmppMessage.body
  }
}

Upvotes: 0

andesta.erfan
andesta.erfan

Reputation: 998

for regular message you should use:

func xmppStream(_ sender: XMPPStream, didReceive message: XMPPMessage) { print(message.body()) }

for MAM purposes you should implement XmppMessageArchiveManagement and it,s delegate.one of it's delegate method is this:

func xmppMessageArchiveManagement(_ xmppMessageArchiveManagement: XMPPMessageArchiveManagement, didReceiveMAMMessage message: XMPPMessage) { print(message.body) }

you can print the archive one with that. be aware that your outgoing packet should be something like this:

`let value = DDXMLElement(name: "value", stringValue: jid)
 let child = DDXMLElement(name: "field")
 child.addChild(value)
 child.addAttribute(withName: "var", stringValue: "with")
 let set = XMPPResultSet(max: 1, before: "")
 XmppMessageArchiveModule.retrieveMessageArchive(at: nil, withFields: [child], with: set)`

max: 1 tell the MAM that you want only the last Message for specific jid. after doing all that please please check this answer [service unavailable error in openfire message archive management

Upvotes: 3

Hardik Thakkar
Hardik Thakkar

Reputation: 15951

Try this code

 - (void)xmppStream:(XMPPStream *)sender didReceiveMessage:(XMPPMessage *)message
    {
        NSString *str = [[message elementForName:@"body"] stringValue];
        NSLog(@"%@",str);
    }

Upvotes: 1

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