CODEWITHSUNDEEP
pythonpython-3.xfloating-point
Tomasz
Tomasz

Reputation: 33

Python 3 Decimal precision

I have an issue with floating-point numbers: 

 a = 0.4812
 b = 0.4813
 a-b
-9.999999999998899e-05
 a = Decimal(0.4812)
 b = Decimal(0.4813)
 a-b
 Decimal('-0.000099999999999988986587595718447118997573852539062500')

How can I get exactly -0.0001?

Upvotes: 3

Views: 87

Answers (2)

juancarlos
juancarlos

Reputation: 631

If you want round it you can use this: round(-0.000099999999999988986587595718447118997573852539062500, 4)

Upvotes: -1

tzaman
tzaman

Reputation: 47790

You need to pass the numbers in as strings to the Decimal constructor, if you use float literals they've already lost precision before the Decimal object gets constructed. 

>>> a = Decimal('0.4812')
>>> b = Decimal('0.4813')
>>> a - b
Decimal('-0.0001')

To illustrate more clearly:

>>> Decimal('0.4812')                                              
Decimal('0.4812')                                                  
>>> Decimal(0.4812)                                                
Decimal('0.481200000000000016608936448392341844737529754638671875')

Upvotes: 2

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