Reputation: 978
I was working on a simple problem and I came up with a recursive function in C++, below is my function.
void test(int arr[],int n,int x = 0){
cout<<arr[x];
for(int i = x+1;i < n;i++){
test(arr, n, i);
}
}
I wonder what will be the time complexity of the above function if anyone can calculate the time complexity for the above method it will be a great help in improving my function.
Upvotes: 0
Views: 529
Reputation: 18838
You can write its recurrent relation likes the following:
T(n) = T(n-1) + T(n-2) + ... + T(1) + 1
Indeed T'(x)
is T(n - x)
and T(1) = 1
(The last one in the realtion is is for cout
). We can see:
T(2) = T(1) + 1 = 2
T(3) = T(2) + T(1) + 1 = 2 + 1 + 1 = 4
T(4) = 4 + 2 + 1 + 1 = 2^2 + 2^1 + 2^0 + 1 = 8
T(5) = 8 + 4 + 2 + 1 + 1 = 2^3 + 2^2 + 2^1 + 2^0 + 1 = 16
.
.
.
T(n) = 2^{n-2} + 2^{n-1} + ... + 2^0 + 1 = 2^{n-1}
Hence, T(n) = \Theta(2^n)
.
Upvotes: 2