CODEWITHSUNDEEP
phphtmlarrayscheckboxforeach
Nat_
Nat_

Reputation: 141

foreach in PHP - how to transfer the values in a variable?

so the problem is, I have a HTML form with checkboxes as an input-option. I want to save all the selected options as a string(!) in one variable.

I'm pretty sure the solution is a foreach-loop, but mine doesn't work. It only returns the last selected value.

How can I fix this?

HTML 

<form action="" method="post">
<label>category:<br/>
     one <input type="checkbox" name ="ber[]" value="one"><br/>
     two <input type="checkbox" name ="ber[]" value="two"><br/>
     thr <input type="checkbox" name ="ber[]" value="three"><br/>
     fou <input type="checkbox" name ="ber[]" value="four"><br/>
</form>

PHP

foreach ($_POST['ber'] as $value) {
$ber = "$value. ', '"
}

Upvotes: 0

Views: 1356

Answers (4)

u_mulder
u_mulder

Reputation: 54831

This is called "implode an array":

$ber = implode(',', $_POST['ber']);
echo $ber;
// or simply
echo implode(',', $_POST['ber']);

Upvotes: 7

user3783243
user3783243

Reputation: 5224

You need to concatenate.

$ber = ''
foreach ($_POST['ber'] as $value) {
    $ber .= "$value. ', '"
}

With your current approach $ber = overwrites the previous value.

A better solution though is implode.

Upvotes: 2

Bhavin
Bhavin

Reputation: 2158

Just change your foreach loop with below foreach loop. You are getting ber in POST not category. So you need to change $_POST['ber'] from $_POST['category'].

$ber = '';
foreach ($_POST['ber'] as $value) {
    $ber .= "$value. ', '"
}

Upvotes: 1

D P
D P

Reputation: 328

You will get the selected checkboxes value in POST array

<?php $_POST['ber']; ?>

Now If you want to assign this array to variable with comma separated

<?php $beer_value = implode(",", $_POST['ber']); ?>

Upvotes: 2

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