CODEWITHSUNDEEP
c#
Michael SH.
Michael SH.

Reputation: 3

Shortening a function

I was tasked with creating a function that receives two numbers and returns True if both are equal and returns False if not. This is what I wrote:

int x = int.Parse(Console.ReadLine());
int y = int.Parse(Console.ReadLine());

if (x == y)
{
    Console.WriteLine("True");
}
if (x != y)
{
    Console.WriteLine("False");
}

I was hinted that it is possible to do this with only one line of code. Couldn't figure how to and would like to see how it's possible.

Upvotes: 0

Views: 104

Answers (4)

RazorShorts
RazorShorts

Reputation: 115

Suppose your using a console to try this theory. The parsing and console reading aside.

    private bool NumbersEqual(int number1, int number2)
    {
        return number1.Equals(number2);
    }

:Edit Without the method 

var number1 = 1;
var number2 = 2;

var equal = number1.Equals(number2);

Or truly truly without variable declarations and 1 line
var equal = 1.Equals(2);

Upvotes: -2

Ric
Ric

Reputation: 13248

using some newer c#7 Out variables:

Console.WriteLine(
    int.TryParse(Console.ReadLine(), out int first) &&
    int.TryParse(Console.ReadLine(), out int second) &&
    first == second ? "True" : "False");

Upvotes: 3

fubo
fubo

Reputation: 45947

Sice Console.WriteLine(true); outputs True you can use

Console.WriteLine(int.Parse(Console.ReadLine()) == int.Parse(Console.ReadLine()));

Upvotes: 4

Tudor
Tudor

Reputation: 62439

Console.WriteLine(int.Parse(Console.ReadLine()) == 
                  int.Parse(Console.ReadLine()) ? "True" : "False");

This will work for any custom words you need to print, just replace the corresponding strings.

Console.WriteLine(int.Parse(Console.ReadLine()) == 
                  int.Parse(Console.ReadLine());

Will also work if you always want to print "True" or "False" since the ToString() of boolean is conveniently capitalized.

Upvotes: 0

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