CODEWITHSUNDEEP
stringbashextractcut
Johannes
Johannes

Reputation: 55

Extracting 2 parts of a String

I've got a String which contains the Output of a command which looks like this:

max. bit rate:      ('2.5 MBit/s', '16.7 MBit/s')

Now I need to extract the "2.5 MBit/s" and the "16.7 MBit/s" in two seperate strings.

The language is bash.

Upvotes: 1

Views: 51

Answers (3)

Mark Setchell
Mark Setchell

Reputation: 208107

Like this in bash without starting any extra external processes:

yourString="max. bit rate:      ('2.5 MBit/s', '16.7 MBit/s')"

IFS="'" read _ rate1 _ rate2 _ <<< "$yourString"

echo $rate1
2.5 MBit/s

echo $rate2
16.7 MBit/s

I am setting the IFS (Input Field Separator) to a single quote, then doing a read with unwanted fields going into a dummy (unused) variable called _.

Upvotes: 2

Cyrus
Cyrus

Reputation: 88999

With regex:

x="max. bit rate:      ('2.5 MBit/s', '16.7 MBit/s')"
[[ $x =~ .*\'(.*)\'.*\'(.*)\'.* ]] && echo "${BASH_REMATCH[1]} ${BASH_REMATCH[2]}"

Output:

2.5 MBit/s 16.7 MBit/s

Upvotes: 1

JNevill
JNevill

Reputation: 50308

with awk:

string1=$(echo "max. bit rate:      ('2.5 MBit/s', '16.7 MBit/s')" | awk -F"'" '{print $2}')
string2=$(echo "max. bit rate:      ('2.5 MBit/s', '16.7 MBit/s')" | awk -F"'" '{print $4}')

with cut:

string1=$(echo "max. bit rate:      ('2.5 MBit/s', '16.7 MBit/s')" | cut -d"'" -f2)
string2=$(echo "max. bit rate:      ('2.5 MBit/s', '16.7 MBit/s')" | cut -d"'" -f4)

Either way we are just splitting the string by a single quote and grabbing the 2nd and 4th fields.

Upvotes: 2

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