Reputation: 532
In the help page of the psych package, it says that I can pass more graphic parameters to the outlier()
function. My syntax is really simple and as follows:
outlier(na.omit(data[,51:56]), plot = TRUE, main = 'my title')
This returns: Error in plot.default(sx, sy, xlab = xlab, ylab = ylab, ...) :
formal argument "main" matched by multiple actual arguments. I have the feeling this means that the function tries to have the default title (by the psych package) as well as the title I give (i.e. my title
).
Is there a way to overwrite this or fix it? Or probably I am doing something that needs to be fixed.
Reproducible example
A <- floor(runif(30, 1,5))
B <- floor(runif(30, 1,5))
C <- floor(runif(30, 1,5))
D <- floor(runif(30, 1,5))
E <- floor(runif(30, 1,5))
f <- floor(runif(30, 1,5))
sample.data <- data.frame(A, B, C, D, E, f)
outlier(sample.data, plot = TRUE, main = 'my title')
Upvotes: 2
Views: 391
Reputation: 35594
I clear the color of title. Hope to solve your problem.
outlier(sample.data, plot = TRUE, col.main = NA)
title("My Title")
Upvotes: 2