CODEWITHSUNDEEP
pythonstringlist
Sina Arzany
Sina Arzany

Reputation: 63

how to compare a string with items in a list , character by character in python

I have a list and I want to compare user input with that list , but character by character. for example user can only input some character and leave the rest by dots. (for example : V...r..n ) How do I can compare strings character by character, and if it only includes all characters by user input (skip the dots)

list1 = ["Vaporeon", "Jolteon", "Flareon", "Espeon", "Umbreon", "Leafeon", "Glaceon", "Sylveon"]
s = input()  # for example "V...r..n"
for i in list1:
    # if s include exactly characters in i (skip the dots)
        print(i)

Upvotes: 0

Views: 111

Answers (4)

jpp
jpp

Reputation: 164623

Here's one way. There are two steps. First make a dictionary mapping indices to relevant characters. Then check for equality for those indices.

L = ["Vaporeon", "Jolteon", "Flareon", "Espeon", "Umbreon", "Leafeon", "Glaceon", "Sylveon"]

s = input()
d = {k: v for k, v in enumerate(s) if v != '.'}

for item in L:
    if (len(s) == len(item)) and all(item[k] == v for k, v in d.items()):
        print(item)

# V...r..n
# Vaporeon

Upvotes: 1

nosklo
nosklo

Reputation: 222802

You can use regular expressions:

import re

list1 = ["Vaporeon", "Jolteon", "Flareon", "Espeon", "Umbreon", "Leafeon", "Glaceon", "Sylveon"]
s = input()  # for example "V...r..n"

re_s = re.compile(''.join('.' if ch == '.' else re.escape(ch) for ch in s) + '$')
for i in list1:
    if re_s.match(i):
        print(i)

EDIT: Another option that seems missing from the other answers is to use itertools.zip_longest:

from itertools import zip_longest

list1 = ["Vaporeon", "Jolteon", "Flareon", "Espeon", "Umbreon", "Leafeon", "Glaceon", "Sylveon"]
s = input()  # for example "V...r..n"
for i in list1:
    if all(c1 == c2 for c1, c2 in zip_longest(i, s) if c2 != '.'):
        print(i)

Upvotes: 2

Koyaanis
Koyaanis

Reputation: 176

There are some hard looking solutions here. I found this to be the easiest and working solution.

list1 = ["Vaporeon", "Jolteon", "Flareon", "Espeon", "Umbreon", "Leafeon", "Glaceon", "Sylveon"]
s = input()  # for example "V...r..n"
matchedList = []
for i in list1:
    inputInList = True
    for letter in s:
        if not letter in i:
            inputInList = False
            break
    if inputInList:
        matchedList.append(i)

print(matchedList)

Upvotes: -1

politinsa
politinsa

Reputation: 3720

There are several ways to solve it, with regex, with the solution of jpp, or with this one:

list1 = ["Vaporeon", "Jolteon", "Flareon", "Espeon", "Umbreon", "Leafeon", "Glaceon", "Sylveon"]
s = input()  # for example "V...r..n"
for word in list1:
    l = len(word)
    c = 0
    flag = True
    while c < l and flag:
        if s[c] != '.':
            if s[c] != word[c]:
                flag = False
        c += 1
    if flag:
        print(word)

Upvotes: 0

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