Reputation: 268
Is it possible to directly unmarshal a list of wrapped elements into a List<String>
in JAXB?
For example I have a XML like:
<TEST>
<MIME_INFO>
<MIME>
<MIME_SOURCE>foo.png</MIME_SOURCE>
<MIME_PURPOSE>normal</MIME_PURPOSE>
</MIME>
<MIME>
<MIME_SOURCE>bar.png</MIME_SOURCE>
<MIME_PURPOSE>normal</MIME_PURPOSE>
</MIME>
</MIME_INFO>
</TEST>
So would it be possible to directly unmarshal this XML file into a List<String>
only containing { "foo.png", "bar.png" }?
I know that you could create a class hierarchy with the correct annotations to perform this unmarshalling but i would like to have a code like:
import java.util.List;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement(name = "TEST")
@XmlAccessorType (XmlAccessType.FIELD)
public class Info {
// -> what annotation to put here?
private List<String> infos;
public List<String> getInfos() {
return infos;
}
}
And the main file:
import java.io.File;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Unmarshaller;
public class UnmarshallingJAXB {
public static void main(String[] args) throws JAXBException {
JAXBContext jaxbContext = JAXBContext.newInstance(Info.class);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
Info info = (Info) jaxbUnmarshaller.unmarshal(new File("test.xml"));
// should output foo.png and bar.png
info.getInfos().forEach(System.out::println);
}
}
Is there any way to do that?
Upvotes: 0
Views: 347
Reputation: 118
Apologies for answering so late, but this is the first hit on Google if search for related problems so it might help anyway.
Yes, it is possible, using
@XmlElementWrapper
in combination
@XmlElement
See this example for more detailed info.
Upvotes: 1