CODEWITHSUNDEEP
c++exceptionerror-handlingtry-catch
Prasanth Madhavan
Prasanth Madhavan

Reputation: 13309

try catch duo in c++

I know that the general method for using the try catch duo is something like this:

try
{
   //your code
}
catch(...)
{
   //any error goes here
}

Is there a way by which catch() catches the error code without giving any input... i.e if I didn't throw an exception but the c compiler did, then the error code can be anything. I just need to catch whatever the error code is and be notified that's all.

Upvotes: 3

Views: 4163

Answers (2)

Fred Foo
Fred Foo

Reputation: 363547

Apparently, you're trying to catch errors from functions that don't throw exceptions but return numerical error codes. That's impossible. The closest you can get is wrapping all your C functions in exception throwing code yourself:

FILE *safe_fopen(char const *path, char const *mode)
{
    FILE *f = std::fopen(path, mode);
    if (f == NULL)
        throw std::runtime_error(std::strerror(errno));
    return f;
}

It is not possible to throw an exception when a program derefences a null pointer or an invalid piece of memory, at least not in a portable manner; when that happens, behavior is simply undefined. There's no error code to check for, just a segfault on most OSs.

But please get your terminology straight. The compiler does not throw an exception, a function may do so, at run-time. The C compiler has very little to do with all this.

Upvotes: 10

user229044
user229044

Reputation: 239270

You don't have to catch everything. If you only want to handle a particular type of exception, only catch that exception:

try {

} catch (MyExceptionType ex) {

}

Upvotes: 0

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