Reputation: 3953
I am using XPATH to parse xml document,please find the xml below
<?xml version="1.0" encoding="UTF-8"?>
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
<soap:Body>
<bookEvent>
<bookName>harry_potter</bookName>
<bookEntity>comic</bookEntity>
<bookEntityId>10987645</bookEntityId>
<bookParameter>
<name>Name1</name>
<value>value1</value>
</bookParameter>
<bookParameter>
<name>Name2</name>
<value>value2</value>
</bookParameter>
<bookParameter>
<name>Name3</name>
<value>value3</value>
</bookParameter>
<bookParameter>
<name>Name4</name>
<value>value4</value>
</bookParameter>
<bookParameter>
<name>Name5</name>
<value>value5</value>
</bookParameter>
</bookEvent>
</soap:Body>
</soap:Envelope>
Here I would like to convert BookParameters to Map like below
{"Name1":"value1","Name2":"value2" etc}
I have tried the below code and i can get a Map but not in the expected format,
try{
Map<String,String> eventParameters = new HashMap<>();
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse("book.xml");
XPathFactory xPathfactory = XPathFactory.newInstance();
XPath xpath = xPathfactory.newXPath();
NodeList nodeList = (NodeList)xpath.compile("//bookEvent//eventParameter").evaluate(doc, XPathConstants.NODESET);
for (int i = 0; i < nodeList.getLength(); i++) {
Node node = nodeList.item(i);
if(node.hasChildNodes()) {
NodeList childNodes = node.getChildNodes();
for (int j = 0; j < childNodes.getLength(); j++) {
Node childNode = childNodes.item(j);
if (childNode.getNodeType() == Node.ELEMENT_NODE) {
System.out.println(childNode.getNodeName()+"::"+childNode.getNodeValue()+"::"+childNode.getTextContent());
eventParameters.put(childNode.getTextContent(),childNode.getTextContent());
}
}
}
}
System.out.println("print map::"+eventParameters);
} catch (Exception e) {
e.printStackTrace();
}
The output looks like this
print map::{Name3=Name3, Name4=Name4, value5=value5, Name5=Name5, value2=value2, value1=value1, value4=value4, value3=value3, Name1=Name1, Name2=Name2}
Please somebody guide me to create a below map from the xml,Any help would be appreciable.
{"Name1":"value1","Name2":"value2" etc}
Upvotes: 0
Views: 1225
Reputation: 1275
Use Below code :
import java.io.File;
import java.util.LinkedHashMap;
import java.util.Map;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
public class ReadXMLFile {
public static Map<String,String> hMap = new LinkedHashMap<>();
public static void main(String argv[]) {
try {
File fXmlFile = new File("C:\\Users\\jaikant\\Desktop\\QUESTION.xml");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
doc.getDocumentElement().normalize();
NodeList nodeList = doc.getElementsByTagName("bookParameter");
for (int parameter = 0; parameter < nodeList.getLength(); parameter++) {
Node node = nodeList.item(parameter);
if (node.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) node;
String name = eElement.getElementsByTagName("name").item(0).getTextContent();
String value = eElement.getElementsByTagName("value").item(0).getTextContent();
hMap.put(name, value);
}
}
} catch (Exception e) {
e.printStackTrace();
}
hMap.forEach((h,k) -> {
System.out.println(h + ":" + k);
});
}
}
It will print exactly what you are looking for.
Upvotes: 1
Reputation: 163322
You can do it as a one-liner in XPath 3.1:
map:merge(//bookParameter!map{string(name): string(value)})
=> serialize(map{'method':'json'})
You can run XPath 3.1 from Java by installing Saxon-HE 9.8 (open source)
Upvotes: 2