Reputation: 9463
MSBuild 3.5
I have the following project structure:
trunk/MainSolution.sln
trunk/Build/MyBuild.Proj
trunk/Library/...
trunk/etc...
So far, I've been using the following property to find out the project root folder:
<RootFolder>$(MSBuildProjectDirectory)\..\</RootFolder>
Everything was working great, until I tried using a copy task that relied on this path. It is not resolving correctly. I basically end up getting something like this which is not valid:
C:\Projects\MyProject\Trunk\Build\..\CodeAnalysis\myfile.xml
So basically, I need to get the full path for (MSBuildProjectDirectory)'s Parent.
Upvotes: 12
Views: 11293
Reputation: 14100
In case someone like me is still interested in this, here is how I did it in 2022 ^_^
<PropertyGroup>
<ParentFolderPath>$([System.IO.Directory]::GetParent($(MSBuildProjectDirectory)))</ParentFolderPath>
<ParentFolder>$([System.IO.Path]::GetFileName($(ParentFolderPath)))</ParentFolder>
...
</PropertyGroup>
I'm using this technique to auto-name the assemblies and default namespaces in the complex solutions.
<AssemblyName>$(ParentFolder).$(MSBuildProjectName)</AssemblyName>
<RootNamespace>$(ParentFolder).$(MSBuildProjectName.Replace(" ", "_"))</RootNamespace>
Upvotes: 2
Reputation: 380
Nowadays with MSBuild 4.0 and above you don't want to use CreateItem or CreateProperty tasks anymore. What you are asking for can be solved easily with msbuild property functions:
<!-- Prints the parent directory's full path. -->
$([System.IO.Path]::GetFullPath('$(MSBuildProjectDirectory)\..'))
If you just want to read the parent directory's folder name you can combine the above statement with the GetFileName property function:
$([System.IO.Path]::GetFileName('$([System.IO.Path]::GetFullPath('$(MSBuildProjectDirectory)\..'))'))
A bit verbose but much better than the other answer as this works outside of targets and can be assigned to a property.
Upvotes: 3
Reputation: 50000
Item metadata is your friend!
<Target Name="GetMSBuildProjectParentDirectory">
<!-- First you create the MSBuildProject Parent directory Item -->
<CreateItem Include="$(MSBuildProjectDirectory)\..\">
<Output ItemName="MSBuildProjectParentDirectory" TaskParameter="Include"/>
</CreateItem>
<!-- You can now retrieve its fullpath using Fullpath metadata -->
<Message Text="%(MSBuildProjectParentDirectory.Fullpath)"/>
<!-- Create a property based on parent fullpath-->
<CreateProperty Value="%(MSBuildProjectParentDirectory.Fullpath)">
<Output PropertyName="CodeFolder" TaskParameter="Value"/>
</CreateProperty>
</Target>
Upvotes: 16