CODEWITHSUNDEEP
cgccoutputbackslash
aambazinga
aambazinga

Reputation: 53

why does \b removes one char written before \b, when used in the mid of the string but not when used at the end?

when \b used inside string.

int main (void)
{
    printf("asdfhjk\bll");
    return 0;
}

output:

asdfhjll

when \b used at the end of the string.

int main (void)
{
    printf("asdfhjkll\b");
    return 0;
}

output:

asdfhjkll

why the last character l is not removed by \b. according to the working of \b, the character preceding the \b is removed. it works fine when used in the middle of the string, but not when used at the end. why?

Upvotes: 1

Views: 133

Answers (2)

iBug
iBug

Reputation: 37227

The character \b is a backspace character. It moves the cursor one position backwards without writing any character to the screen.

Consider your first example: asdfhjk\bll. Before "printing" the backspace character, the screen looks like this:

asdfhjk
       ^

... where ^ indicates the cursor position. And after printing \b, it goes this

asdfhjk
      ^

The the last two characters overwrite k:

asdfhjll
        ^

For the second example asdfhjkll\b. before printing \b:

asdfhjkll
         ^

and after:

asdfhjkll
        ^

No character is erased, but the cursor has been shifted one char backwards. If you print anything else, the last l gets overridden.

Upvotes: 4

Angew is no longer proud of SO
Angew is no longer proud of SO

Reputation: 171127

\b means "move the output position one character backwards." So when you output e.g. x\by, x is written, then the output cursor is rewound before the x just written, and then the y overwrites the x.

However, when there's no output following the \b, the cursor simply remains where it was. Further output would then overwrite the last visible character written.

Upvotes: 1

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