CODEWITHSUNDEEP
javascript
Great Khan 2016
Great Khan 2016

Reputation: 515

Filtering my an object

This code works for filtering my one Id.

let symbols =([
  {symbols:"XFX", id:1},
  {symbols:"XFF", id:2},
  {symbols:"XEE", id:20},
])

function getStocksOver(stocks, id){
  return stocks.filter(function(stock,index){
    return stock.id !=id;
  });
}

console.log(getStocksOver(symbols,1))

Now i would like to be able to filter by an object

 let symbolsDeleted =([
  {symbols:"XFX", id:1},
  {symbols:"XFF", id:2},
])

Does anyone know a way of doing this cause i really stuck.

Upvotes: 0

Views: 60

Answers (2)

D. Seah
D. Seah

Reputation: 4592

I think you can use map and filters

const symbolsDeleted =([
  {symbols:"XFX", id:1},
  {symbols:"XFF", id:2},
])

let symbols =([
  {symbols:"XFX", id:1},
  {symbols:"XFF", id:2},
  {symbols:"XEE", id:20},
])

function getStocksOver(stocks, oObject) {
  const keys = oObject.map(o => o.id);
  return stocks.filter((s) => !keys.includes(s.id));
}

console.log(getStocksOver(symbols, symbolsDeleted));

Upvotes: 1

Daniel
Daniel

Reputation: 11192

Instead of comparing every stock.id to a single id, you can create an additional filter that filters your symbolsDeleted array by the stock id.

The length of the filter result will be 0 if there are no matches.

In that case you return true to the outer filter function.

If a match is found, false is returned.

let symbolsDeleted =([
  {symbols:"XFX", id:1},
  {symbols:"XFF", id:2},
])

let symbols =([
  {symbols:"XFX", id:1},
  {symbols:"XFF", id:2},
  {symbols:"XEE", id:20},
])

function getStocksOver(stocks, objArray){
  return stocks.filter(function(stock, index) {
    return objArray.filter(function(value) {
      return value.id == stock.id
    }).length == 0;
  });
}

console.log(getStocksOver(symbols, symbolsDeleted))

Upvotes: 1

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