CODEWITHSUNDEEP
javascriptarrays
Doug
Doug

Reputation: 31

Filter / sorting Array

spt_curr_A = ["acb|123|N", "bca|234|N", "dcs_abc|134|Y", "abc|432|N", "def_bca|243|Y"]

for (var i = 0; i < spt_curr_A.length; i++){
   sl = spt_curr_A[i].split("|");

   console.log("Split: " + sl);
}

Once it is split, I only want the the ones with "N" to be display as sl. I have tried several different ways with no luck.

Upvotes: 1

Views: 105

Answers (5)

OliverRadini
OliverRadini

Reputation: 6466

Arrays have methods which mean you don't always need to iterate over them manually in order to get data from them. Methods such as map and filter return an array, so can be chained together.

Working with arrays in this way makes code easier to read and adjust. In the example I give below, I use map and filter to get only the data which is useful to us. Then, forEach allows us to iterate the remaining items and log them to the console.

If you're interested in learning more about array methods, this article is a good place to start.

Your original code could be adjusted to make a similar check:

spt_curr_A = ["acb|123|N", "bca|234|N", "dcs_abc|134|Y", "abc|432|N", "def_bca|243|Y"]

for (var i = 0; i < spt_curr_A.length; i++){
   sl = spt_curr_A[i].split("|");
   
   if (sl[2] === 'N') {
    console.log("Split: " + sl);
   }   
}

But you may find it easier to work with code that uses map and filter instead of a for loop:

spt_curr_A = ["acb|123|N", "bca|234|N", "dcs_abc|134|Y", "abc|432|N", "def_bca|243|Y"]

spt_curr_A
  .map(item => item.split('|'))
  .filter(item => item[2] === 'N')
  .forEach(item => console.log(`Split ${item}`))

Upvotes: 5

Vikasdeep Singh
Vikasdeep Singh

Reputation: 21766

Option 1:

Loop through the array and check if element of array contains |N at end using str.endsWidth(). Below is working code:

var spt_curr_A = ["acb|123|N", "bca|234|N", "dcs_abc|134|Y", "abc|432|N", "def_bca|243|Y"];

var new_array = [];

for (var i in spt_curr_A) {
  if (spt_curr_A[i].endsWith("|N")) {
    new_array.push(spt_curr_A[i])
  }
}

console.log(new_array);

Option 2:

You can check if in sl array element at index 2 is N or not like below:

var spt_curr_A = ["acb|123|N", "bca|234|N", "dcs_abc|134|Y", "abc|432|N", "def_bca|243|Y"]

for (var i = 0; i < spt_curr_A.length; i++) {
  sl = spt_curr_A[i].split("|");
  if (sl[2] === "N") {
    console.log("Split: " + sl);
  }
}

Upvotes: 1

sridhar..
sridhar..

Reputation: 2133

Do filter first and then you can do any operatin 

let spt_curr_A = ["acb|123|N", "bca|234|N", "dcs_abc|134|Y", "abc|432|N", "def_bca|243|Y"]

spt_curr_A = spt_curr_A.filter((str) => {
 return str.indexOf('|N') !== -1
});
spt_curr_A= spt_curr_A.splice("|")
console.log(spt_curr_A)

Upvotes: 0

Thieri
Thieri

Reputation: 213

What about Array.includes()?

spt_curr_A = ["acb|123|N", "bca|234|N", "dcs_abc|134|Y", "abc|432|N", "def_bca|243|Y"]

for (var i = 0; i < spt_curr_A.length; i++){
   sl = spt_curr_A[i].split("|");

    if(sl.includes("N"))
    {
        console.log("Split: " + sl);
    }
}

Upvotes: 0

Ele
Ele

Reputation: 33726

An alternative is using the function Array.prototype.filter.

Assuming every element has three sections (two pipes).

let spt_curr_A = ["acb|123|N", "bca|234|N", "dcs_abc|134|Y", "abc|432|N", "def_bca|243|Y"],
    fn = (s) => s.split("|").pop() === "N",
    filtered = spt_curr_A.filter(fn);

console.log(filtered);
.as-console-wrapper { max-height: 100% !important; top: 0; }

Upvotes: 0

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