CODEWITHSUNDEEP
javaarrays
Monet Walkens
Monet Walkens

Reputation: 15

java increasing array stored value

I would like to know if the following code would increase the array value to the next array value every time it runs.

For e.g, on the first run, it stores value in count[1] of the array, on the next run does it store the value in count[2]?

public static void getadminName(){
        String[] name= new String[20];
        for (int count=0;count<name.length;count++){
            name[count]= JOptionPane.showInputDialog(null,"Please enter 
            admin's name:");
            String scount=Integer.toString(count);
            name[count]= scount+1;
            break;
        } 
    }

Upvotes: 1

Views: 106

Answers (1)

Green Cloak Guy
Green Cloak Guy

Reputation: 24691

Remove the break statement and the code should do approximately what you want it to. Keep in mind that name is an array of strings, with twenty elements. When you do name[count], you're referring to the countth element of that array, which is a String.

You notice that the for loop has three parts:

  • int count=0; declares an integer named 'count', initialized to the value 0.
  • count < name.length declares a "termination condition" - if, before executing the code inside the loop, this condition is false, then the loop ends. In this case, it runs until the variable count has a value greater than the length of the array name.
  • count++ is executed immediately after each iteration of the loop finishes.

The sum, in this case, is that you start with count=0, accessing the first element of name, and then you do things in the loop, and then count increases by one, and the code inside the loop runs again, until count is greater than the length of name.

The statement break specifically jumps out of the loop, regardless of whether it otherwise would have. That's what you don't want to do here - you want to continue looping.

Upvotes: 3

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