CODEWITHSUNDEEP
php
Ben
Ben

Reputation: 25827

How check memory location of variable in php?

How check memory location of variable in php?

Upvotes: 23

Views: 25842

Answers (6)

Bailey Parker
Bailey Parker

Reputation: 15903

I'm fairly certain this isn't possible in PHP. You might be able to create an extension to do this, but I can't see any use for it. Memory addresses are useless within PHP scripts since the interpreter handles all the internal variable works. Outside of PHP (say manipulating a memory address with C or C++) would be dangerous to say the least. I would expect you could crash a script and possibly your interpreter if you modified a memory address used by a PHP script while it was executing.
If you are looking for internal pointers in PHP, though, take a look into references. It might take a few reads to wrap your head around them, but if you need to pass by reference, look into them. Quick example:

<?php
function change( &$name ) { $name = "Yosef"; }
$name = "John";
change( $name );
echo $name;
?>

Upvotes: 2

Mark Baker
Mark Baker

Reputation: 212522

If you need to know if $varA is a reference to $varB, then you're out of luck: the PHP innards does not present this information to the developer.

However, you can extract some information about references by parsing the output from var_dump or debug_zval_dump(). Read the relevant manual sections, and see this question for some details.

And have a ready of this (PDF) article by Derick Rethans on references in PHP.

Watch out for the refcount when using debug_zval_dump() because the function always creates an additional reference within itself, incrementing the value by 1

Upvotes: 12

jameshfisher
jameshfisher

Reputation: 36619

As others have said, the API does not expose a way to retrieve a value's address. However, you can compare the addresses of two values, given two variables. Here's a function that tests whether two variables reference the same value:

function vars_reference_same_value(&$a, &$b)
{
  $not_b = $b === 0 ? 1 : 0;
  $a_orig = $a;
  $a = $not_b;
  $is_ref = $b === $not_b;
  $a = $a_orig;
  return $is_ref;
}

(This is the same as @infinity's answer, but perhaps more comprehensible.)

Upvotes: 2

Alex Rashkov
Alex Rashkov

Reputation: 10015

To test if one variable is a reference to another you can do the following: 

function is_ref_to(&$a, &$b)
{
    $t = $a;
    if($r=($b===($a=1))){ $r = ($b===($a=0)); }
    $a = $t;
    return $r;
}

Upvotes: 6

mario
mario

Reputation: 145512

If you need to know if a variable is a reference to another, then debug_zval_dump() is the only option.

Upvotes: 6

Felipe Cardoso Martins
Felipe Cardoso Martins

Reputation: 892

Sorry, but this is not possible [1]

They are not like C pointers; for instance, you cannot perform pointer arithmetic using them

[1] http://php.net/manual/en/language.references.php

Upvotes: 4

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