CODEWITHSUNDEEP
c++
niro
niro

Reputation: 977

how to call .exe file within c++ program?

I want to use a exe file (convert.exe), inside my C++ program. This "exe" file change my output file format to another format. when, i use this convert.exe from my command-prompt (cmd), i have to type like this;

convert -in myfile -out convertedfile -n -e -h

where;

myfile= name of the file, I obtain from my c++ program convertedfile= result of the "convert.exe" file -n, -e, -h = are some parameters (columns) that i need to use to get output file with my desired data columns.

i tried with system(convert.exe). but, it does not work as i did not know how to use all those parameters.

Upvotes: 15

Views: 48995

Answers (5)

dm76
dm76

Reputation: 4270

The std::system function expects a const char *, so how about you try

system("convert -in myfile -out convertedfile -n -e -h")

Then, if you want to be a little more flexible, you use std::sprintf can create a string with the right elements in it and then pass it to the system() function like so:

// create a string, i.e. an array  of 50 char
char command[50];  

// this will 'fill' the string command with the right stuff,
// assuming myFile and convertedFile are strings themselves
sprintf (command, "convert -in %s -out %s -n -e -h", myFile, convertedFile);   

// system call
system(command);

Upvotes: 18

raetza
raetza

Reputation: 29

system (command); from stdlib.h

Since you don't want parallel execution wouldn't three consecutive calls to the execs with system () work for you?

Upvotes: 1

Yuriy Petrovskiy
Yuriy Petrovskiy

Reputation: 8188

Use one of these:

int execl(char * pathname, char * arg0, arg1, ..., argn, NULL);
int execle(char * pathname, char * arg0, arg1,..., argn, NULL, char ** envp);
int execlp(char * pathname, char * arg0, arg1,..., argn, NULL);
int execlpe(char *  pathname, char * arg0, arg1,..., argn, NULL, char ** envp);int execv(char * pathname, char * argv[]);
int execve(char * pathname, char * argv[], char ** envp);
int execvp(char * pathname, char * argv[]);
int execvpe(char * pathname, char * argv[],char ** envp);

exec() family of functions creates a new process image from a regular, executable file...

Upvotes: 1

rkellerm
rkellerm

Reputation: 5522

You can use Win32 API CreateProcess.

Upvotes: 2

fretje
fretje

Reputation: 8382

Have a look at the ShellExecute function:

ShellExecute(NULL, "open", "<fully_qualified_path_to_executable>\convert.exe", 
                           "-in myfile -out convertedfile -n -e -h", 
                           NULL, SW_SHOWNORMAL);

Upvotes: 4

Related Questions