Reputation: 5302
How can i do a nested select using Laravel raw query?
SELECT day_of_week, AVG(order_count) average_order FROM
(
SELECT DAYNAME(order_date) day_of_week,
DAYOFWEEK(order_date) day_num,
TO_DAYS(order_date) date,
count(*) order_count
FROM orders
GROUP BY date
) temp
GROUP BY day_of_week
ORDER BY day_num
This is what I tried so far:
DB::table('(
SELECT DAYNAME(order_date) day_of_week,
DAYOFWEEK(order_date) day_num,
TO_DAYS(order_date) date,
count(*) order_count
FROM orders
GROUP BY date
) temp')
->select(DB::raw('day_of_week, AVG(order_count) average_order'))
->groupBy(DB::raw('day_of_week'))
->orderBy(DB::raw('day_num'))
->get();
This is not working, but so far this query is very close.
By the way, I am using Laravel 5.6.
Thanks!
Upvotes: 0
Views: 239
Reputation: 25906
Use DB::raw()
in table()
and don't use it in groupBy()
and orderBy()
:
DB::table(DB::raw('(
SELECT DAYNAME(order_date) day_of_week,
DAYOFWEEK(order_date) day_num,
TO_DAYS(order_date) date,
count(*) order_count
FROM orders
GROUP BY date
) temp'))
->select('day_of_week', DB::raw('AVG(order_count) average_order'))
->groupBy('day_of_week')
->orderBy('day_num')
->get();
You can also use fromSub()
:
$from = DB::table('orders')
->selectRaw(
'DAYNAME(order_date) day_of_week,
DAYOFWEEK(order_date) day_num,
TO_DAYS(order_date) date,
count(*) order_count'
)->groupBy('date');
DB::query()->fromSub($from, 'temp')
->select('day_of_week', DB::raw('AVG(order_count) average_order'))
->groupBy('day_of_week')
->orderBy('day_num')
->get();
Upvotes: 2
Reputation: 1211
Try This , but surely it's need to edit
DB::table('orders')
->select(DB::raw('(SELECT order_date AS day_of_week, order_date AS day_num, order_date AS date FROM orders GROUP BY date)'))
->groupBy(DB::raw('day_of_week'))
->orderBy(DB::raw('day_num'))
->get();
Upvotes: 0