CODEWITHSUNDEEP
pythonpython-3.xoopdictionaryparameter-passing
glamredhel
glamredhel

Reputation: 336

Pythonic way to pass dictionary as argument with specific keys

What am I trying to solve: I want to create an object that is based on a dictionary. The object should contain some additional methods that are out of the scope of this question. There dictionary passed must contain a known set of keys.

What obviously will work is:

   class DictBasedObject(object):
      def __init__(self, dictionary: {})
         if 'known_key_1' in dictionary:
            self.known_key_1 = dictionary['known_key_1']
         if 'known_key_2' in dictionary:
            self.known_key_2 = dictionary['known_key_2']
         ...

however this way is rather cumbersome.

How I am trying to solve: I would like to pass the dictionary as argument to a method, but with possibly specifying of the dictionary key-names/value-types, like:

   class DictBasedObject(object):
      def __init__(self, dictionary: {'known_key_1': str,
                                      'known_key_2': int,
                                      ...})
         self.known_key_1 = dictionary['known_key_1']
         self.known_key_2 = dictionary['known_key_2']
         ...

Obviously not much better, but at least one step towards 'more elegant'.

Is there an elegant and pythonic manner to solve this?

Upvotes: 2

Views: 985

Answers (1)

blhsing
blhsing

Reputation: 106883

You can either use the setattr function:

for k, v in dictionary.items():
    setattr(self, k) = v

or simply update the __dict__ attribute of the object:

self.__dict__.update(dictionary)

Upvotes: 2

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