CODEWITHSUNDEEP
javascriptbinaryoperator-keyword
Sw0ut
Sw0ut

Reputation: 791

Why 1 & 1 === 1 returns true while 2 & 2 === 2 returns false?

In the console, when I type 1 & 1 it returns 1, that's basically why 1 & 1 === 1 returns true.

For 2 & 2 it returns 2 but 2 & 2 === 2 returns false

Why ?

console.log("1 & 1: ", 1 & 1);
console.log("1 & 1 === 1: ", 1 & 1 === 1);
console.log("2 & 2: ", 2 & 2);
console.log("2 & 2 === 2: ", 2 & 2 === 2);
console.log("typeof(2): ", typeof 2);
console.log("typeof(2 & 2): ", typeof(2 & 2));

Upvotes: 3

Views: 385

Answers (2)

ndotie
ndotie

Reputation: 2150

in javascript when you write 2 & 2 this doesnt mean 2 && 2 instead it convert 2 into 32 bits numbers and perform AND operation, the same AND you learned in binary numbers where the numbers wont be 2 again therefore (2 & 2) === 2 wont return true, as (1 & 1) === 1 returns true because on binary operation 1 AND 1 returns 1 as well

Upvotes: 0

Sw0ut
Sw0ut

Reputation: 791

As @jonrsharpe said, it doesn't return false, it returns 0. It's evaluated as 2 & (2 === 2). (2 & 2) === 2 is true.

Thanks

Upvotes: 1

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