CODEWITHSUNDEEP
regexvim
madsk
madsk

Reputation: 13

VIM: How do I reformat lists dependent on type of brackets using regex?

I'm trying to write a crude code formatter in VIM using regex and it's generally going okay but I'm stuck on this one problem: How do I reformat a list only, and if only it's inside of certain type of brackets. Say for example I want to reformat

a = [1, 2, 3, 4]

into

a = 
[1,
2,
3,
4]

but not do the operation on

b = |1, 2, 3, 4|

?

so far, I've used this which finds all occurrences of a word + a comma + any character and replaces it with a comma and a return. 

au BufWrite <buffer> %s/\w\zs,\ze./,\r/ge

Upvotes: 1

Views: 58

Answers (2)

Alan G&#243;mez
Alan G&#243;mez

Reputation: 378

You also can use the regex:

:%s/^.*|\n\zs\|,/,\r/g

Which mean ^.*|\n that match every line that contains the character |, then the command \zs surpass this selection, now can match every comma from remaining lines...

Another more general way is:

:%s/^\(\(.*\[.*\)\@!.\)*$\n\zs\|,/,\r/g

which ^\(\(.*\[.*\)\@!.\)*$\n mean to match every lines that not contains [.

Upvotes: 0

sidyll
sidyll

Reputation: 59297

You could use a mix of :s and substitute() to work on the match. Considering the following text, for example:

a = [1, 2, 3, 4]
b = |1, 2, 3, 4|

Using:

:%s/\s*\[.\{-}]/\=substitute(submatch(0), '\s\+', '\n', 'g')

Returns:

a =
[1,
2,
3,
4]
b = |1, 2, 3, 4|

What it does is to match the [...] and then replace every space inside it with a newline.

Upvotes: 1

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