CODEWITHSUNDEEP
djangopython-3.x
Bussiere
Bussiere

Reputation: 1144

Custom error page with django 2.0

here is my code in urls.py : 

def handler500(request, exception):
    response =  HttpResponseServerError('error.html', {},
                                  context_instance=RequestContext(request))
    response.status_code = 500
    return response

but i have a : 

TypeError: handler500() missing 1 required positional argument: 'exception'

What am i missing ?

edit bis the whole code : 

from django.contrib import admin
from django.urls import path
from django.urls import include

from django.conf import settings
from django.conf.urls.static import static
from django.http import HttpResponseServerError

urlpatterns = [path("admin/", admin.site.urls)]
urlpatterns += [path("", include("Exchange.urls"))]

urlpatterns += static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)


from django.shortcuts import render_to_response
from django.template import RequestContext


def handler404(request, exception, template_name='404.html'):
    response = render_to_response('404.html', {},
                                  context_instance=RequestContext(request))
    response.status_code = 404
    return response


def handler500(request,exception):
    response =  HttpResponseServerError('error.html', {},
                                  context_instance=RequestContext(request))
    response.status_code = 500
    return response

so here is the whole urls.py file, it seems that my post is mostly code so i have to add more details like the fact this is the django 2.0 version or it runs on python3.6 on a ubuntu os.

Upvotes: 0

Views: 5216

Answers (1)

Ralf
Ralf

Reputation: 16485

If you take a look at the docs, there it defines the 500 handler with just one positional argument.

Change you code from

def handler500(request, exception):

to

def handler500(request):

Let us know if that works.

Just a hint: django docs on customizing error views suggests placing your view functions in views.py and just adding the string name to your urls.py, like:

# in views.py
def handler500(request):
    ...

# in urls.py
handler500 = 'mysite.views.handler500'

Upvotes: 6

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