Reputation: 75
I have:
+---+-------+-------+
| id| var1| var2|
+---+-------+-------+
| a|[1,2,3]|[1,2,3]|
| b|[2,3,4]|[2,3,4]|
+---+-------+-------+
I want:
+---+-------+-------+-------+-------+-------+-------+
| id|var1[0]|var1[1]|var1[2]|var2[0]|var2[1]|var2[2]|
+---+-------+-------+-------+-------+-------+-------+
| a| 1| 2| 3| 1| 2| 3|
| b| 2| 3| 4| 2| 3| 4|
+---+-------+-------+-------+-------+-------+-------+
The solution provided by How to split a list to multiple columns in Pyspark?
df1.select('id', df1.var1[0], df1.var1[1], ...).show()
works, but some of my arrays are very long (max 332).
How can I write this so that it takes account of all length arrays?
Upvotes: 6
Views: 8910
Reputation: 2477
This solution will work for your problem, no matter the number of initial columns and the size of your arrays. Moreover, if a column has different array sizes (eg [1,2], [3,4,5]), it will result in the maximum number of columns with null values filling the gap.
from pyspark.sql import functions as F
df = spark.createDataFrame(sc.parallelize([['a', [1,2,3], [1,2,3]], ['b', [2,3,4], [2,3,4]]]), ["id", "var1", "var2"])
columns = df.drop('id').columns
df_sizes = df.select(*[F.size(col).alias(col) for col in columns])
df_max = df_sizes.agg(*[F.max(col).alias(col) for col in columns])
max_dict = df_max.collect()[0].asDict()
df_result = df.select('id', *[df[col][i] for col in columns for i in range(max_dict[col])])
df_result.show()
>>>
+---+-------+-------+-------+-------+-------+-------+
| id|var1[0]|var1[1]|var1[2]|var2[0]|var2[1]|var2[2]|
+---+-------+-------+-------+-------+-------+-------+
| a| 1| 2| 3| 1| 2| 3|
| b| 2| 3| 4| 2| 3| 4|
+---+-------+-------+-------+-------+-------+-------+
Upvotes: 7