Reputation: 279
Manager table :
create table Manager(id integer, name varchar(100));
insert into Manager(id, name) values(1, "M1");
insert into Manager(id, name) values(2, "M2");
insert into Manager(id, name) values(3, "M3");
Employee table along with manager id(m_id)
create table Employee(id integer, m_id integer, name varchar(100));
insert into Employee(id, m_id, name) values(11, 1,"E1");
insert into Employee(id, m_id, name) values(12, 1,"E2");
insert into Employee(id, m_id, name) values(13, 2,"E3");
Executed query:
select M.id, M.name, count(E.id) from Manager as M, Employee as E where E.m_id=M.id group by E.m_id, M.id, M.name;
Output:
1 M1 2
2 M2 1
Expected output:
1 M1 2
2 M2 1
3 M3 0
Please help me how to include M3 manager along with 0 employee assigned to him?
Upvotes: 0
Views: 46
Reputation: 1275
You should use a left join
SELECT M.id, M.name, count(E.id) from Manager as M LEFT JOIN Employee as E ON E.m_id=M.id GROUP BY E.m_id, M.id, M.name;
Upvotes: 2