CODEWITHSUNDEEP
arraysangulartypescriptjavascript-objects
Luisinhoc
Luisinhoc

Reputation: 33

Find items in the array based on the inner array condition

How to find id in an array that is inside of an array of objects

Example:

let arrayobjects = [{ 
    id: 1, 
    name: "oinoin", 
    description: ["one", "two", "three"]
}, { 
    id: 2, 
    name: "zatata", 
    description: ["four", "five", "six"]
}];

How can I find the id of the word "two" ?

Upvotes: 2

Views: 481

Answers (5)

Sinan Guclu
Sinan Guclu

Reputation: 1087

For examples sake, here is a version with old javascript.

  var arrayobjects = [
    { 
        id: 1, 
        name: "oinoin", 
        description: ["one", "two", "three"]
    }, { 
        id: 2, 
        name: "zatata", 
        description: ["four", "five", "six"]
    }
  ];

  function findId (desc, arr) {
    var idx, arrObjLen = arr.length, results = [];

    // Iterate through the first array
    for (idx = 0; idx < arrObjLen; idx ++) {
      // If the value exists in the 'description' array
      if (arr[idx].description.indexOf(desc) > -1) {
        // Add it to the results array
        results.push(arr[idx].id)
      }
    }
    return results;
  }

  console.log('Results:', findId('five', arrayobjects));

You could also use Array#reduce if you want to minimise the amount of code you're using:

const arrayobjects = [
    { 
        id: 1, 
        name: "oinoin", 
        description: ["one", "two", "three"]
    }, { 
        id: 2, 
        name: "zatata", 
        description: ["four", "five", "six"]
    }
  ];

console.log(

  arrayobjects.reduce((col, { id, description }) => 
    // If description contains the desired value
    description.includes('two')
      // Add the id to the collector array
      ? [ ...col, id ] : col, [])

);

Upvotes: 0

Suren Srapyan
Suren Srapyan

Reputation: 68635

If you need more than one item, you can filter the array via Array#filter, check if property description for each item contains word two via Array#includes (ES7), then map the result to get only id of those items using Array#map.

let arrayobjects = [
      { id: 1, name: "oinoin", description: ["one", "two", "three"] }, 
      { id: 2, name: "zatata", description: ["four", "five", "six"] }
];

const ids = arrayobjects.filter(item => item.description.includes('two'))
                        .map(item => item.id);
                        
console.log(ids);

If you have only one item, you can just use Array#find and do same checking

let arrayobjects = [
      { id: 1, name: "oinoin", description: ["one", "two", "three"] }, 
      { id: 2, name: "zatata", description: ["four", "five", "six"] }
];

const item = arrayobjects.find(item => item.description.includes('two'));
                        
console.log(item.id);

Upvotes: 8

Sk96
Sk96

Reputation: 113

This snippet might be what you are looking for

arrayobjects.filter( ele => ele.description.includes("two")).map(ele => ele.id)

output :[1]

Upvotes: 3

Manoz
Manoz

Reputation: 6587

You can try with indexOf too

arrayobjects.filter(f=>f.description.indexOf('two')>-1)[0].id


let arrayobjects = [
{ 
    id: 1, 
    name: "oinoin", 
    description: ["one", "two", "three"]
}, { 
    id: 2, 
    name: "zatata", 
    description: ["four", "five", "six"]
}
];

console.log(arrayobjects.filter(f=>f.description.indexOf('two')>-1)[0].id);

Note

.filter returns an array. So if multiple items are found with two in description then you do not use index [0]. This is just an example of one item in array.

Upvotes: 1

Akhil Aravind
Akhil Aravind

Reputation: 6130

There may be more efficient way, but i some how find a solution. iterate through the array and match the array item.

var arrayobjects = [{ id: 1, name: "oinoin", description: ["one", "two", "three"]}, { id: 2, name: "zatata", description: ["four", "five", "six"]}];
arrayobjects.forEach(item => {
  if(item.description.indexOf('two') != -1 ){
  console.log(item.id)
}
})

Upvotes: 1

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