CODEWITHSUNDEEP
bashawksed
soosap
soosap

Reputation: 1445

Split a string using numerals as delimiter in bash

120h2m12s => 120h 2m 12s

120a2b12c => 120a 2b 12c

I want to split whenever a number appears after a non-number.

How can I achieve this in bash?

Here is what I tried so far:

Upvotes: 1

Views: 94

Answers (4)

glenn jackman
glenn jackman

Reputation: 246807

I'd use perl, it's very succinct:

echo "$time" | perl -pe 's/(\D)(\d)/$1 $2/g'

But if you want bash:

$ echo "$time";
120h2m12s

$ while [[ $time =~ ([[:alpha:]])([[:digit:]]+) ]]; do 
    time=${time/${BASH_REMATCH[1]}${BASH_REMATCH[2]}/${BASH_REMATCH[1]} ${BASH_REMATCH[2]}}
done

$ echo "$time"
120h 2m 12s

Upvotes: 0

RavinderSingh13
RavinderSingh13

Reputation: 133518

Could you please try following too:

echo "120h2m12s" | sed 's/[0-9]*[a-z]*/& /g'

Output will be as follows.

120h 2m 12s

Check with another self made dummy example too:

echo "120h2m12s12131313ddd" | sed 's/[0-9]*[a-z]*/& /g'
120h 2m 12s 12131313ddd

Upvotes: 1

Ed Morton
Ed Morton

Reputation: 203532

$ echo '120h2m12s' | sed 's/[0-9]*/ &/g'
 120h 2m 12s

You end up with a leading space using the above, if that matters then:

$ echo '120h2m12s' | sed 's/\([^0-9]\)\([0-9]\)/\1 \2/g'
120h 2m 12s

Upvotes: 1

Proyag
Proyag

Reputation: 2262

echo "120h2m12s" | sed -e 's/\([a-zA-Z]\)\([0-9]\)/\1 \2/g'

Adds a space in between when it sees a letter followed by a digit.

Upvotes: 0

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