CODEWITHSUNDEEP
javaarrays
Riddler
Riddler

Reputation: 15

Empty integer array in java

Write a function that takes an array as input and returns an array of 2 numbers. The returned array contains the sum of even numbers and sum of odd numbers from the input.

If any of the input is null it should be treated as an empty array

Example: Input:
[30, 18, 2, 83, 20, 71]
Output:
[70, 154]

Input:
[14, 11, 10, 67, 41]
Output:
[24, 119]

Input: [36, 24, -82, 29, 44, -3, -100, -5, 49] Output: [-78, 70]

The function that I have written is

public int[] getSumOfEvensAndOdds(int[] input) {
        
        int x[] = input;
        int even = 0, odd = 0;
        for (int i = 0; i < x.length; i++) {
            if (x[i] % 2 == 0)
                even += x[i];
            else
                odd += x[i];
        }
        int[] ans={even, odd};
        return ans;
    }

But how should I incorporate the part of the empty array?

Upvotes: 1

Views: 15519

Answers (6)

user2903536
user2903536

Reputation: 1812

Empty array may be return like this return new int[]{}

Upvotes: 0

Gurankas
Gurankas

Reputation: 239

public int[] getSumOfEvensAndOdds(int[] input) {

        int x[] = input;
        int even = 0, odd = 0;
        for (int i = 0; i < x.length; i++) {
        if(x[i] != null)    //in case array contains elements which aren't null
        {
            if (x[i] % 2 == 0)
                even += x[i];
            else
                odd += x[i];
        }
        else   //in case the array has null array elements
        {
           even = 0;
           odd = 0;
        }
        int[] ans={even, odd};
        return ans;
    }

Upvotes: 0

Pantelis Bouboulis
Pantelis Bouboulis

Reputation: 47

You need something like this:

public class Test {

public static int[] getSumOfEvensAndOdds(int[] input) {
    int[]   def = {0,0};

    if (input != null && input.length!=0) {
        int x[] = input;
        int even = 0, odd = 0;
        for (int i = 0; i < x.length; i++) {
            if (x[i] % 2 == 0)
                even += x[i];
            else
                odd += x[i];
        }
        int[] ans = {even, odd};
        return ans;
    }

    return def;
}

public static void main(String [ ] args){
    int[]   ar = {10,20,30,40,50,60,71,80,90,91};
    int[]   res;

    res = getSumOfEvensAndOdds(ar);
    System.out.println("Result: " + res[0] + " " + res[1]);

    int[]   ar2 = {};
    res = getSumOfEvensAndOdds(ar2);
    System.out.println("Result: " + res[0] + " " + res[1]);

    int[]   ar3 = null;
    res = getSumOfEvensAndOdds(ar3);
    System.out.println("Result: " + res[0] + " " + res[1]);
}

}

I use input!=null to check whether the array is null and input.length!=0 to check if its size is 0. Also, in the main method I give three examples.

Upvotes: 0

user2575725
user2575725

Reputation:

if any of the input is null it should be treated as an empty array

Why not just check for null value?

public int[] getSumOfEvensAndOdds(int[] input) {
    int even = 0, odd = 0;
    if(null != input){
        for (int i: input) {
            if (0 == i % 2){
                even += i;
            } else{
                odd += i;
            }
        }
    }
    return new int[]{even, odd};
}

Upvotes: 2

Consti P
Consti P

Reputation: 455

Your question is just about arrays being empty. A quick search got me this: How can I check whether an array is null / empty?

Upvotes: -1

Henry
Henry

Reputation: 43728

Check if input is null first. If it is, work on an empty array instead:

int x[] = input == null ? new int[0] : input;

Upvotes: 4

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