CODEWITHSUNDEEP
pythonstringpython-3.xdictionarydictionary-comprehension
Paul Gwamanda
Paul Gwamanda

Reputation: 302

Get values for (almost) matching keys in 2 dictionaries and join them

So I want to get values for (almost) matching keys in 2 dictionaries and join them. I tried:

dict3 = {key:dict1[key].strip() for key in dict2.keys() if key.partition('__')[0] in dict1}

...but I dont get any results because it's not finding any matches, my dicts are below, I know i'm close but I'm missing something:

dict1:

{
    "h1__display-3": "",
    "h1__display-3_text-white_text-center": "",
    "h1__mt-4": "",
    "h1__mt-5": "",
    "h1__mt-5_kakabum": "",
    "h1__my-4": "",
    "h2__card-title": "",
    "h2__mt-4": "",
    "h2__my-4": ""
}

dict2:

{
    "h1": "<h1>[]</h1>",
    "h2": "<h2>[]</h2>"
}

Desired outcome:

{
    "h1": "<h1>[]</h1>",
    "h1__display-3": "<h1>[]</h1>",
    "h1__display-3_text-white_text-center": "<h1>[]</h1>",
    "h1__mt-4": "<h1>[]</h1>",
    "h1__mt-5": "<h1>[]</h1>",
    "h1__mt-5_kakabum": "<h1>[]</h1>",
    "h1__my-4": "<h1>[]</h1>",
    "h2": "<h2>[]</h2>",
    "h2__card-title": "<h2>[]</h2>",
    "h2__mt-4": "<h2>[]</h2>",
    "h2__my-4": "<h2>[]</h2>"
}

I was hoping that running the first line of code would work, but I dont think i have the syntax right.

Upvotes: 1

Views: 39

Answers (1)

Patrick Haugh
Patrick Haugh

Reputation: 61032

Breaking the dict construction out into an ordinary loop mkaes it a little easier to follow. We want

res = {}
for k in dict1:
    key = k.split('__')[0]
    if key in dict2:
        res[k] = dict2[key]

which is equivalent to 

res = {k: dict2[k.split('__')[0]] for k in dict1 if k.split('__')[0] in dict2}

This doesn't add h1 and h2 as keys, but that's easily accomplished with 

res.update(dict2)

Upvotes: 2

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