CODEWITHSUNDEEP
pythonstringpython-3.xlistpython-datetime
Justin Besteman
Justin Besteman

Reputation: 398

How to find all dates within a list of dates with Python3

I have list of UTC dates like so:

['2018-07-29T15:58:22.111904Z', '2018-07-29T15:59:22.033263Z', '2018-07-29T16:01:22.103157Z', '2018-07-30T11:41:22.032661Z', '2018-07-30T11:42:22.042215Z', '2018-07-31T12:31:21.062671Z']

This is not the full list. What I need is to grab all the dates that are found in the entire list.

So for this list:

['2018-07-29', '2018-07-30', '2018-07-31']

Would be returned.

How would this be accomplished with Python3?

Upvotes: 1

Views: 61

Answers (1)

jpp
jpp

Reputation: 164693

You can use a set comprehension with string slicing:

L = ['2018-07-29T15:58:22.111904Z', '2018-07-29T15:59:22.033263Z',
     '2018-07-29T16:01:22.103157Z', '2018-07-30T11:41:22.032661Z',
     '2018-07-30T11:42:22.042215Z', '2018-07-31T12:31:21.062671Z']

res = {i[:10] for i in L}

Result:

print(res)

{'2018-07-30', '2018-07-31', '2018-07-29'}

If you need a list and do not care about order, use list(res).

If you need a sorted list, use sorted(res).

If you wish to work with datetime objects, which is highly recommended, you should convert to datetime and use the date method. Here's one way with the 3rd party dateutil module:

from dateutil import parser

res = {parser.parse(i).date() for i in L}

print(res)

{datetime.date(2018, 7, 29),
 datetime.date(2018, 7, 30),
 datetime.date(2018, 7, 31)}

List conversion and sorting are possible, exactly as before.

Upvotes: 3

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