Reputation: 2243
I have the following dataframes:
df1 = pd.DataFrame({'col1': ['A','M','C'],
'col2': ['B','N','O'],
# plus many more
})
df2 = pd.DataFrame({'col3': ['A','A','A','B','B','B'],
'col4': ['M','P','Q','J','P','M'],
# plus many more
})
Which look like these:
df1:
col1 col2
A B
M N
C O
#...plus many more
df2:
col3 col4
A M
A P
A Q
B J
B P
B M
#...plus many more
The objective is to create a dataframe containing all elements in col4
for each col3
that occurs in one row in df1
. For example, let's look at row 1 of df1
. We see that A
is in col1
and B
is in col2
. Then, we go to df2
, and check what col4
is for df2[df2['col3'] == 'A']
and df2[df2['col3'] == 'B']
. We get, for A
: ['M','P','Q']
, and for B
, ['J','P','M']
. The intersection of these is['M', 'P']
, so what I want is something like this
col1 col2 col4
A B M
A B P
....(and so on for the other rows)
The naive way to go about this is to iterate over rows and then get the intersection, but I was wondering if it's possible to solve this via merging techniques or other faster methods. So far, I can't think of any way how.
Upvotes: 1
Views: 49
Reputation: 24221
This should achieve what you want, using a combination of merge
, groupby
and set intersection:
# Getting tuple of all col1=col3 values in col4
df3 = pd.merge(df1, df2, left_on='col1', right_on='col3')
df3 = df3.groupby(['col1', 'col2'])['col4'].apply(tuple)
df3 = df3.reset_index()
# Getting tuple of all col2=col3 values in col4
df3 = pd.merge(df3, df2, left_on='col2', right_on='col3')
df3 = df3.groupby(['col1', 'col2', 'col4_x'])['col4_y'].apply(tuple)
df3 = df3.reset_index()
# Taking set intersection of our two tuples
df3['col4'] = df3.apply(lambda row: set(row['col4_x']) & set(row['col4_y']), axis=1)
# Dropping unnecessary columns
df3 = df3.drop(['col4_x', 'col4_y'], axis=1)
print(df3)
col1 col2 col4
0 A B {P, M}
If required, see this answer for examples of how to 'melt' col4
.
Upvotes: 1