Reputation: 1055
I don't have deep knowledge about c++.
I've implemented the smart pointer to prevent the issues caused by raw pointer. (memory leak)
The code is following for the smart pointer.
#ifndef SMARTPOINTER
#define SMARTPOINTER
class RC
{
private:
int count; // Reference count
public:
RC(){ count = 0; }
void AddRef()
{
// Increment the reference count
count++;
}
int Release()
{
// Decrement the reference count and
// return the reference count.
if(count==0) return 0;
return --count;
}
};
template < typename T > class SP
{
private:
T* pData; // pointer
RC* reference; // Reference count
public:
SP() : pData(0), reference(0)
{
// Create a new reference
reference = new RC();
// Increment the reference count
reference->AddRef();
}
SP(T* pValue) : pData(pValue), reference(0)
{
// Create a new reference
reference = new RC();
// Increment the reference count
reference->AddRef();
}
SP(const SP<T>& sp) : pData(sp.pData), reference(sp.reference)
{
// Copy constructor
// Copy the data and reference pointer
// and increment the reference count
reference->AddRef();
}
~SP()
{
// Destructor
// Decrement the reference count
// if reference become zero delete the data
if(reference->Release() == 0)
{
delete pData;
delete reference;
}
}
T& operator* ()
{
return *pData;
}
T* operator-> ()
{
return pData;
}
SP<T>& operator = (const SP<T>& sp)
{
// Assignment operator
if (this != &sp) // Avoid self assignment
{
// Decrement the old reference count
// if reference become zero delete the old data
if(reference->Release() == 0)
{
delete pData;
delete reference;
}
// Copy the data and reference pointer
// and increment the reference count
pData = sp.pData;
reference = sp.reference;
reference->AddRef();
}
return *this;
}
};
#endif // SMARTPOINTER
My question is following..
When using this smart pointer class as below
SP<MyObject> ptrObject; //MyObject class is the custom class.
MyObject *ptr = new MyObject;
ptrObject = ptr; //This invokes the SP(T *) constructor.. why?
//Though operator = ( T*) is not defined.
At this time,though the operator=(T*)
function is not defined, why is the constructor of the smart pointer,SP(T* pValue) , called?
I thought that the constructor is called when the class object is created.
Please explain this, thanks.
Upvotes: 0
Views: 563
Reputation: 142
Implicit conversions are performed whenever an expression of some type T1 is used in context that does not accept that type, but accepts some other type T2;
in particular:
This helps you.
https://www.ibm.com/support/knowledgecenter/en/SSLTBW_2.3.0/com.ibm.zos.v2r3.cbclx01/implicit_conversion_sequences.htm
Upvotes: 1