Reputation: 301
guys, I am trying to submit my form using ajax but I don't know exactly what happened it's not posting the values to my table in the database, This is the first time I am using ajax for form submit can anyone help me what mistake I have done.
Here is my view code:
<html>
<head>
<link href='http://fonts.googleapis.com/css?family=Source+Sans+Pro|Open+Sans+Condensed:300|Raleway' rel='stylesheet' type='text/css'>
<script type='text/javascript' src="<?php echo base_url(); ?>assets/theme1/js/jquery-2.1.3.min.js"></script>
<!-- <script type="text/javascript"> -->
<script type = "text/javascript">
// Ajax post
$(document).ready(function() {
$('form').submit(function(e) {
e.preventDefault();
var organisation_name = $("input#organisation_name").val();
jQuery.ajax({
type: "POST",
url: "<?php echo base_url(); ?>" + "Organisation/createOrg",
dataType: 'json',
data: { organisation_name: organisation_name },
success: function(res) {
if (res) {
// Show Entered Value
jQuery("div#result").show();
jQuery("div#value").html(res.organisation_name);
}
}
});
});
});
</script>
<div class="modal fade" id="createGroup" tabindex="-1" role="dialog" aria-labelledby="createGroup" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content" id="modal-content">
<form action="" id="user-groups-create" class="form-horizontal" method="post">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button>
<h4 class="modal-title" id="myModalLabel">Create a New Organisation</h4>
</div>
<div class="modal-body" id="modal-body">
<div class="form-group">
<label for="group_name" class="col-sm-4 control-label">New Organisation Name : </label>
<div class="col-md-8">
<input type="text" id="organisation_name" name="organisation_name" class="form-control" placeholder="Organisation Name" />
</div>
</div>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
<button type="submit" value="submit" class="btn btn-primary submit" id="submit">Create Organisation</button>
</div>
</form>
</div>
</div>
</div>
Here is my controller's method createOrg:
public function createOrg() {
$this->form_validation->set_error_delimiters('<div class="error">', '</div>');
//Validating Name Field
$this->form_validation->set_rules('organisation_name', 'organisation_name', 'required|min_length[5]|max_length[15]');
if ($this->form_validation->run() == FALSE) {
$this->session->set_flashdata('error', 'Organisation name need to be more than 3 characters and less than 15.');
redirect('Organisation', $error);
} else {
//Setting values for tabel columns
$data = array(
'organisation_name' => $this->input->post('organisation_name')
);
//Transfering data to Model
$this->Org_model->orgInsert($data);
$this->session->set_flashdata('success', 'Organisation created.');
//Loading View
redirect('Organisation');
}
}
Here is my Model's method orgInsert:
function orgInsert($data) {
// Inserting in Table(organisation)
$this->db->insert('organisation', $data);
}
Can anyone help me what mistake I have done and I have checked my code properly I didn't find exactly where I have done a mistake and I want my modal popup should be there after submitting it until a user clicks on the close button. when I try to keep alert after jQuery.ajax({
it is not coming alert.. and I can able to get the value from var organisation_name
in alert...
Thanks in advance.
Upvotes: 0
Views: 59
Reputation: 9707
Hope this will work you :
$('#user-groups-create').on('submit',function(e){
var organisation_name = $("#organisation_name").val();
$.ajax({
type: "POST",
url: "<?=site_url('Organisation/createOrg');?>",
dataType: 'json',
data: {'organisation_name': organisation_name},
success: function(res) {
if (res)
{
alert(res);
window.location.href = "<?=site_url('Organisation');?>";
$("div#result").show();
$("div#value").html(res.organisation_name);
}
},
});
e.preventDefault();
});
Your controller's method createOrg
should be like this :
public function createOrg()
{
$data = array(
'organisation_name' => $this->input->post('organisation_name')
);
//Transfering data to Model
$this->Org_model->orgInsert($data);
$this->session->set_flashdata('success', 'Organisation created.');
echo json_encode($data);
exit;
}
}
Upvotes: 1
Reputation: 301
Working by changing the script to like this
<script type="text/javascript">
// Ajax post
$(document).ready(function() {
$('form').submit(function(e){
e.preventDefault();
var organisation_name = $("input#organisation_name").val();
$.ajax({
type: "POST",
url: "<?php echo base_url(); ?>" + "Organisation/createOrg",
dataType: "html",
data: {organisation_name: organisation_name},
success: function(data) {
alert('success');
}
});
});
});
</script>
Upvotes: 0