Reputation: 557
Hello all and sorry if the title was worded poorly. I'm having a bit of trouble wrapping my head around how to solve this issue I have encountered. I would have liked to simply pass a dict as the value for this key in my json obj but sadly I have to pass it as a string. So, I have a json dict object that looks like this
data = {"test": "Fuzz", "options": "'{'size':'Regular','connection':'unconnected'}'"}
. Obviously, I would prefer that the second dict value weren't a string representation of a dictionary but rather a dictionary. Is the best route here to just strip the second and second to last single quotes for the data[options] or is there a better alternative?
Sorry for any confusion. This is how the json object looks after I perform
json.dump(data, <filename>)
The value for options can be thought of as another variable say x and it's equivalent to '{'size':'Regular','connection':'unconnected'}'
I could do x[1:-1] but I'm not sure if that is the most pythonic way to do things here.
Upvotes: 0
Views: 963
Reputation: 31339
Given OP's comments I suggest the following:
json
module (or the format you've chosen) to load the dataThe data should look like this:
raw_data = {"test": "Fuzz", "options": "{\"size\": \"Regular\", \"connection\": \"unconnected\"}"}
And the code should look like this:
raw_options = raw_data['options']
options = json.loads(raw_options)
data = {**raw_data, 'options': options}
Upvotes: 0
Reputation: 11881
import ast
bad_string_dict = "'{'size':'Regular','connection':'unconnected'}'"
good_string_dict = bad_string_dict.strip("'")
good_dict = ast.literal_eval(good_string_dict)
print(good_dict)
You will have to strip quotation mark, no other way around
Upvotes: 1